All categories

3 years ago

If 3 + 0.7 is equal to 0.7 plus a number, what do you know about the number?

Mathematics

1 answer:

Delicious77 [7]3 years ago

5 0

Answer:

I'm not sure of the answer choices but your answer would be 3.

Step-by-step explanation:

We know that 3 + 0.7 = 3.7, you can take this information and reverse it. 3.7 - 0.7 = 3.

You might be interested in

Find the slope between the two points given. Then, use the slope and the first point to write the equation of the line in Point-

Vera_Pavlovna [14]

M(slope)= -5/4 point-slope(y-y1=m(x-x1)) so it would be y-5= -5/4(x+4)

3 0

2 years ago

Read 2 more answers

How can you minimize the risk from your Investments

aliina [53]

By investing in a variety of investment options

4 0

3 years ago

Read 2 more answers

6. Choose the step to take to solve this equation for x.

DanielleElmas [232]

Answer:

add 7 to the right!

X=8+7

X=15

5 0

2 years ago

Read 2 more answers

Micheal took his brother to the movies. Micheal paid regular price, but it cost $2 less for his brother at the child price. It c

iren [92.7K]

It cost $5 for his brother's ticket.

Step-by-step explanation:

Let,

Micheal's ticket price= x

His brother ticket price = y

According to given statement;

x+y=12 Eqn 1

y = x-2 Eqn 2

Putting value of y from Eqn 2 in Eqn 1

$x+(x-2)=12\\x+x-2=12\\2x=12+2\\2x=14\\$

Dividing both sides by 2;

$\frac{2x}{2}=\frac{14}{2}\\x=7$

Putting x=7 in Eqn 2

$y=7-2\\y=5$

It cost $5 for his brother's ticket.

Keywords: linear equation, substitution method

Learn more about linear equations at:

#LearnwithBrainly

8 0

3 years ago

Find the equation, (f(x) = a(x - h)2 + k), for a parabola containing point (2, -1) and having (4, -3) as a vertex. What is the s

Nataliya [291]

Answer:

$f(x)=\frac{1}{2}x^2-4x+5$

Step-by-step explanation:

A parabola is written in the form

$f(x)=a((x-h)^2+k)$ (1)

where:

$h$ is the x-coordinate of the vertex of the parabola

$ak$ is the y-coordinate of the vertex of the parabola

$a$ is a scale factor

For the parabola in the problem, we know that the vertex has coordinates (4,-3), so we have:

$h=4$ (2)

$ak=-3$

From this last equation, we get that $a=\frac{-3}{k}$ (3)

Substituting (2) and (3) into (1) we get the new expression:

$f(x)=-\frac{3}{k}((x-4)^2+k) = -\frac{3}{k}(x-4)^2 -3$ (4)

We also know that the parabola contains the point (2,-1), so we can substitute

x = 2

f(x) = -1

Into eq.(4) and find the value of k:

$-1=-\frac{3}{k}(2-4)^2-3\\-1=-\frac{3}{k}\cdot 4 -3\\2=-\frac{12}{k}\\k=-\frac{12}{2}=-6$

So we also get:

$a=-\frac{3}{k}=-\frac{3}{-6}=\frac{1}{2}$

So the equation of the parabola is:

$f(x)=\frac{1}{2}((x-4)^2 -6)$ (5)

Now we want to rewrite it in the standard form, i.e. in the form

$f(x)=ax^2+bx+c$

To do that, we simply rewrite (5) expliciting the various terms, we find:

$f(x)=\frac{1}{2}((x^2-8x+16)-6)=\frac{1}{2}(x^2-8x+10)=\frac{1}{2}x^2-4x+5$

6 0

3 years ago