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3 years ago

Hi please answer this xoxo will mark brainliest

Mathematics

2 answers:

ELEN [110]3 years ago

8 0

since isosceles has 2 sides that are equal then,

270 - 108 = 162

divide 162 by 2

162 ÷ 2 = 81

so, C

emmasim [6.3K]3 years ago

8 0

Answer:

A.)

Step-by-step explanation:

108 + 100 + 62 = 270

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Convert 5x + 6y = -5 to slope-intercept form. Simplify your answer

ruslelena [56]

Slope intercept form is y=mx+b. In this case, I believe it's y= -5/6x -5/6.

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3 years ago

A cylindrical can without a top is made to contain 25 3 cm of liquid. What are the dimensions of the can that will minimize the

Basile [38]

Answer:

Therefore the radius of the can is 1.71 cm and height of the can is 2.72 cm.

Step-by-step explanation:

Given that, the volume of cylindrical can with out top is 25 cm³.

Consider the height of the can be h and radius be r.

The volume of the can is V= $\pi r^2h$

According to the problem,

$\pi r^2 h=25$

$\Rightarrow h=\frac{25}{\pi r^2}$

The surface area of the base of the can is = $\pi r^2$

The metal for the bottom will cost $2.00 per cm²

The metal cost for the base is =$(2.00× $\pi r^2$ )

The lateral surface area of the can is = $2\pi rh$

The metal for the side will cost $1.25 per cm²

The metal cost for the base is =$(1.25× $2\pi rh$ )

$=\$2.5 \pi r h$

Total cost of metal is C= 2.00 $\pi r^2$ + $2.5 \pi r h$

Putting $h=\frac{25}{\pi r^2}$

$\therefore C=2\pi r^2+2.5 \pi r \times \frac{25}{\pi r^2}$

$\Rightarrow C=2\pi r^2+ \frac{62.5}{ r}$

Differentiating with respect to r

$C'=4\pi r- \frac{62.5}{ r^2}$

Again differentiating with respect to r

$C''=4\pi + \frac{125}{ r^3}$

To find the minimize cost, we set C'=0

$4\pi r- \frac{62.5}{ r^2}=0$

$\Rightarrow 4\pi r=\frac{62.5}{ r^2}$

$\Rightarrow r^3=\frac{62.5}{ 4\pi}$

⇒r=1.71

Now,

$\left C''\right|_{x=1.71}=4\pi +\frac{125}{1.71^3}>0$

When r=1.71 cm, the metal cost will be minimum.

Therefore,

$h=\frac{25}{\pi\times 1.71^2}$

⇒h=2.72 cm

Therefore the radius of the can is 1.71 cm and height of the can is 2.72 cm.

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3 years ago

What is a equation for 11 5 and b

Phoenix [80]

Answer: i need more information in order to help

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2 years ago

Find the value of x.

bekas [8.4K]

10 - 2x = 120
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2 years ago

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11. How many different ways can the 16 numbered pool balls be placed in a line on the pool table?

nikklg [1K]

Answer:

The number of ways are 16! or 20,922,789,888,000.

Step-by-step explanation:

Consider the provided information.

We need to determine the number of different ways 16 numbered pool balls be placed in a line on the pool table.

For the first place we have 16 balls.

For the second place we have 15 balls left.

Similarly for the third place we have 14 balls as two balls are already arranged and so on.

Or we can say that this is the permutation of 16 things taking 16 at a time.

Thus the number of ways are: $16!$ or $^{16}P_{16}$

$16!=16\times15\times14\times13......\times2\times1=20,922,789,888,000$

Hence, the number of ways are 16! or 20,922,789,888,000.

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3 years ago