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Zina [86]
3 years ago
6

A pool contains 3600 cubic feet of water. If the length of the pool is 30 feet, the width is 16 feet, and the depth of the pool

is the same throughout, how deep is the pool?
Mathematics
1 answer:
IgorLugansk [536]3 years ago
6 0
30 times 16 is 480
3600/480=7.5 (the depth of the pool)
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Which expressions are equivalent to 0.5*m*n*4<br> 2(m+n)<br> 0.5m + 4n<br> None of the above
Mnenie [13.5K]
0.5*m*n*4=0.5*4*m*n = 2*m*n = 2mn

2(m+n) = 2m + 2n ≠ 2mn

0.5m + 4n ≠ 2mn

The answer is None of the above
8 0
3 years ago
On a recent trip to the movies , you see a advertisement for 2 adult tickets and 6 child tickets for $60. Write and equation usi
Igoryamba

Answer:

2A + 6C = $60

Step-by-step explanation:

When asked to write and equation or expression, literally. O verte what is in the question to an algebra. The only difference between expression and equation is that equation shows what goes on the other side of the equals sign when expression doesn’t

Hope this helps

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4 0
3 years ago
Explain why a quadratic equation with a positive discriminant has two real solutions, a quadratic equation with a negative discr
Bad White [126]

Answer:

A quadratic equation can be written as:

a*x^2 + b*x + c = 0.

where a, b and c are real numbers.

The solutions of this equation can be found by the equation:

x = \frac{-b +- \sqrt{b^2 - 4*a*c} }{2*a}

Where the determinant is D = b^2 - 4*a*c.

Now, if D>0

we have the square root of a positive number, which will be equal to a real number.

√D = R

then the solutions are:

x = \frac{-b +- R }{2*a}

Where each sign of R is a different solution for the equation.

If D< 0, we have the square root of a negative number, then we have a complex component:

√D = i*R

x = \frac{-b +- C*i }{2*a}

We have two complex solutions.

If D = 0

√0 = 0

then:

x = \frac{-b +- 0}{2*a} = \frac{-b}{2a}

We have only one real solution (or two equal solutions, depending on how you see it)

3 0
3 years ago
Will mark BRAINLIEST!!!!
Virty [35]

Answer:

The first one is your answer.

Step-by-step explanation:

What you do is you have to look at the 2/18 in the square root. That can come out to be 1/3. So you know that a 3 is going to be on the bottom.

Now you look at the x^5. What you do is you make it until you have 5 x's like this x, x, x, x, x. You then put them in pairs of two.

x,x   x,x   x.  There are two pairs of two so that comes out.

So you have 1x^2sqrtx/3. which is the first one.

#1 is your answer.

6 0
3 years ago
Find the roots of the polynomial equation x^3+2x^2+3x+6=0
rodikova [14]

Answer: x=−2

Step-by-step explanation:

x^3+2x^2+3x+6=0

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x=−2


4 0
3 years ago
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