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3 years ago

Please help me with my question

Mathematics

2 answers:

Flauer [41]3 years ago

8 0

Answer:

14.28 %

Step-by-step explanation:

cost price of an umbrella = 280

selling price of an umbrella = 320

profit% = SP - CP / CP *100%

=320 - 280/280 * 100

=40/280 * 100

=4000/280

=14.28

Fed [463]3 years ago

7 0

Answer:

14.3%

Step-by-step explanation:

subtract 320 with 280 which is 40. divide 40 with 280 and multiply that will 100. You get 14.3%

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1/8= 12 true or false

N76 [4]

Answer:

false

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

7-18=______+______=______

ra1l [238]

7-18= a negative number. We know that it'll equal a negative number because the minued(7) is less than the subtrahend(18), which results in a negative number (if both are positive).

We can make an addition problem from this. We can have 18 turn negative and 7 stay positive, and we'll get the same answer.

7+-18=7-18

7-18=7+-18=11

8 0

3 years ago

Lucy, Sam, and Bob served a total of 72 orders Monday at the school cafeteria. Bob served 3 times as many orders as Lucy. Lucy s

julia-pushkina [17]

let

x-------> the number of Lucy's orders

y-------> the number of Sam's orders

z-------> the number of Bob's orders

we know that

<u> $x+y+z=72$ </u>----> equation A

$z=3x$ -----> equation B

$x=8+y-----> y=x-8$ -----> equation C

substitute equation B and C in equation A

$x+(x-8)+3x=72\\ 5x=72+8\\ 5x=80\\x=16\\$

find z

$z=3*16=48$

find y

$y=x-8------> y=16-8=8$

therefore

<u>the answer is</u>

the number of Lucy's orders is $16$

the number of Sam's orders is $8$

the number of Bob's orders is $48$

4 0

3 years ago

cylinder shaped can needs to be constructed to hold 200 cubic centimeters of soup. The material for the sides of the can costs 0

Dafna11 [192]

Answer:

Radius=2.09 cm

Height,h=14.57 cm

Step-by-step explanation:

We are given that

Volume of cylinderical shaped can=200 cubic cm.

Cost of sides of can=0.02 cents per square cm

Cost of top and bottom of the can =0.07 cents per square cm

Curved surface area of cylinder= $2\pi rh$

Area of circular base=Area of circular top= $\pi r^2$

Total cost,C(r)= $0.02\times 2\pi rh+2\pi r^2\times 0.07$

Volume of cylinder, $V=\pi r^2 h$

$200=\pi r^2 h$

$h=\frac{200}{\pi r^2}$

Substitute the value of h

$C(r)=0.02\times 2\pi r\times \frac{200}{\pi r^2}+2\pi r^2\times 0.07$

$C(r)=\frac{8}{r}+0.14\pi r^2$

Differentiate w.r.t r

$C'(r)=-\frac{8}{r^2}+0.28\pi r$

$C'(r)=0$

$-\frac{8}{r^2}+0.28\pi r=0$

$0.28\pi r=\frac{8}{r^2}$

$r^3=\frac{8}{0.28\pi}=9.095$

$r=(9.095)^{\frac{1}{3}}=2.09$

Again, differentiate w.r.t r

$C''(r)=\frac{16}{r^3}+0.28\pi$

Substitute the value of r

$C''(2.09)=\frac{16}{(2.09)^3}+0.28\pi=2.63>0$

Therefore,the product cost is minimum at r=2.09

h= $\frac{200}{\pi (2.09)^2}=14.57$

Radius of can,r=2.09 cm

Height of cone,h=14.57 cm

4 0

3 years ago

A data set includes the following grades: 98, 94, 93, 82, 61, 80. Suppose that 61 is removed from the data. How is the median af

andre [41]

Answer:b

Step-by-step explanation:

A data with values

98,94,93,82,61,80 is given

If we arrange the number according to their values

61,80,82,93,94,98

Median of set

$\frac{82+93}{2}=87.5$

Now if 61 is removed then

80,82,93,94,98 are the remaining data

so New median is 93

So the median is increased by 5.5

Therefore option b is correct

5 0

4 years ago

Please help me with my question ​

Please help me with my question