Answer:
there r algebra calulators you could use
Step-by-step explanation:
Answer:
6±√10
Step-by-step explanation:
x^2-12x+26=0
x= ± √10 +6
6±√10
(210 + 159.80 + 301.25 + x) / 4 = 638.40
(671.05 + x ) / 4 = 638.40 ...multiply both sides by 4
671.05 + x = 638.40 * 4
671.05 + x = 2553.6
x = 2553.6 - 671.05
x = 1882.55 <=== the 4th number
The quadratic formula, for the equation ax² + bx + c = 0, where a ≠ 0, is:
x = (-b plus or minus √(b² - 4ac)) ÷ 2a. From this formula...
...the discriminant of ax² + bx + c = 0 is given by Δ = b² - 4ac.
If Δ > 0, then there are two real roots. If Δ < 0, there are no real solutions.
If Δ = 0, there is exactly 1 real root.
Using this, we can substitute the coefficients for j into the discriminant formula. Δ = 3² - 4(-4)(-28), which equals 9 - (448), which is clearly less than 0.
So there are NO REAL ROOTS to -4j² + 3j - 28 = 0
Hope this helps!
Answer:
400
Step-by-step explanation:
2500=x+(x+500)+(3x)
2500=5x+500
2500-500=5x
2000=5x
x=400
