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igomit [66]
3 years ago
9

The number of games in the first round of a chess tournament is equal to 2×2×2×2×2×2. Write the number of games using an exponen

t.​
Mathematics
1 answer:
Naily [24]3 years ago
8 0

Answer:

2^6

Step-by-step explanation:

2 is being multiplied 6 times meaning it would be 2 to the 6th power.

You might be interested in
An 8-sided die is formed when two square pyramids are attached by their bases. The perimeter of the base shape is 6 centimeters.
lawyer [7]

Answer:

7.5cm²

Complete question:What is the surface area of the 8-sided figure?

Step-by-step explanation:

Consider the half of the 8-sided die i.e the pyramid ABCDE:

As the base is 6 of the perimeter, so each side of the base is 6/4=3/2

Now, the distance between the tallest points is 2 cm, so the height of Pyramid ABCDE is 1 cm.

Considering the right triangle EOM:

EO=1, OM= 3/4 (it is half of AB=3/2) and EM is the hypothenuse, so by the pythagorean theorem length of EM is 

\sqrt{1+ ( \frac{3}{4} )^{2} }=  \sqrt{1+ \frac{9}{16} }= \sqrt{ \frac{25}{16} }= \frac{5}{4}   (cm)

5. So side EBC has area  

\frac{1}{2}BC*EM=  \frac{1}{2}* \frac{3}{2}* \frac{5}{4}= \frac{15}{16}

6. The total area is 8*Area(EBC)=8* \frac{15}{16}= \frac{15}{2}=7.5 ( cm^{2} )

3 0
3 years ago
I need help on these questions pls
Lady bird [3.3K]
3a. Megan's car has more gas
3b. 2/3=66.666% and 3/5= 60% so 6 2/3 gallons

5. 108.09-15.45= 92.64


3 0
4 years ago
What is the length of a leg of a right triangle if the hypotenuse is 9 inches and the other leg is 8 inches.
adelina 88 [10]

Answer:

√17 or 4.12 inches

Step-by-step explanation:

√9²-8²=√81-64=√17 inches

or 4.12 inches

5 0
3 years ago
A rectangle is 12.5 m wide and 18.24 m long.
strojnjashka [21]
The answer is
D. 228.00 m2
I hope i helped
4 0
3 years ago
Read 2 more answers
Lucy is using a one-sample t ‑test based on a simple random sample of size n = 22 to test the null hypothesis H 0 : μ = 16.000 c
slega [8]

Answer:

The value of test statistic is 1.338

Step-by-step explanation:

We are given the following in the question:  

Population mean, μ = 16.000

Sample mean, \bar{x} = 16.218

Sample size, n = 22

Alpha, α = 0.05

Sample standard deviation, s = 0.764

First, we design the null and the alternate hypothesis

H_{0}: \mu = 16.000\text{ cm}\\H_A: \mu < 16.000\text{ cm}

We use one-tailed t test to perform this hypothesis.

Formula:

t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{\sigma}{\sqrt{n}} }

Putting all the values, we have

t_{stat} = \displaystyle\frac{16.218 - 16.000}{\frac{0.764}{\sqrt{22}} } = 1.338

Thus, the value of test statistic is 1.338

4 0
4 years ago
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