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3 years ago

9

The number of games in the first round of a chess tournament is equal to 2×2×2×2×2×2. Write the number of games using an exponen

t.

1 answer:

Naily [24]3 years ago

8 0

Answer:

2^6

Step-by-step explanation:

2 is being multiplied 6 times meaning it would be 2 to the 6th power.

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The speed of light is estimated at 186,000 miles per second rounded to the nearest thousand miles per second.

Sedbober [7]

It was rounding to the nearest THOUSAND.

We are looking at the thousands place, keep that in mind.

Remember: everything 5 and above is rounded up, everything below 5 is rounded down.

186,789 is above 500, it is rounded to 187,000

186,899 is above 500, it is rounded to 187,000

185,990 is above 500, it is rounded to 186,000

and 185,190 is below 500, it is rounded to 185,000

Only one matches the criteria of the question:

185,990 is above 500, it is rounded to 186,000

therefore the answer is 185,990 miles per second

Have a fantastic day!

Read more on Brainly.com - brainly.com/question/10945335#readmore

8 0

3 years ago

Select an operation to make the equation true.

MrRa [10]

Add. I’m not sure because there is a - besides the 15.

Explanation - 12 + 15 = 27.

Hopefully this helps. Have a blessed one. God loves you. ☺️

3 0

2 years ago

If h is 36in, w is 28in, and A is 6112in to the second power, what is the length of the box

OlgaM077 [116]

The length of the box would be 12288.

5 0

3 years ago

Please graph y= 1/2x–3<br> Please i need help with this <3

erik [133]

Answer:

coordinates are 6, -3

Step-by-step explanation:

When it's plotted out onto a graph, the answer comes down to 6, -3 (also remember, it's X then Y)

6 0

3 years ago

PLEASE HELP!!! Find the equation , in the standard form of the line passing through the points (3,-4) and (5,1)

ExtremeBDS [4]

$\bf \begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
% (a,b)
&&(~ 3 &,& -4~) 
% (c,d)
&&(~ 5 &,& 1~)
\end{array}
\\\\\\
% slope = m
slope = m\implies 
\cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{1-(-4)}{5-3}\implies \cfrac{1+4}{5-3}\implies \cfrac{5}{2}
\\\\\\
% point-slope intercept
\stackrel{\textit{point-slope form}}{y- y_1= m(x- x_1)}\implies y-(-4)=\cfrac{5}{2}(x-3)\implies y+4=\cfrac{5}{2}x-\cfrac{15}{2}$

$\bf y=\cfrac{5}{2}x-\cfrac{15}{2}-4\implies y=\cfrac{5}{2}x-\cfrac{23}{2}\impliedby 
\begin{array}{llll}
\textit{now let's multiply both}\\
\textit{sides by }\stackrel{LCD}{2}
\end{array}
\\\\\\
2(y)=2\left( \cfrac{5}{2}x-\cfrac{23}{2} \right)\implies 2y=5x-23\implies \stackrel{standard~form}{-5x+2y=-23}
\\\\\\
\textit{and if we multiply both sides by -1}\qquad 5x-2y=23$

side note: multiplying by the LCD of both sides is just to get rid of the denominators

5 0

3 years ago