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Serhud [2]
3 years ago
8

Solve x2 – 12x + 26 = 0 by completing the square.

Mathematics
1 answer:
kykrilka [37]3 years ago
3 0

Answer:

6±√10

Step-by-step explanation:

x^2-12x+26=0

x= ± √10  +6

6±√10

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My answer -

<span>1. Use symbols (not words) to express quotient
 

2. Use exponent symbol (^) to denote exponents

3. Just write out question number, question, and choices. No need for extra information (such as points). Also, don't leave blank lines between choices. This extraneous that we don't need just makes your whole question very very long, and means a lot of scrolling on our part.
 

4. You should only post 2 or 3 questions at a time.


1) (6x^3 − 18x^2 − 12x) / (−6x) = −x^2 + 3x + 2 ----> so much simpler to read !

2) (d^7 g^13) / (d^2 g^7) = d^(7−2) g^(13−7) = d^5 g^6 ----> much easier to read !

3) (4x − 6)^2 = 16x^2 − 24x − 24x + 36 = 16x^2 − 48x + 36

4) (x^2 / y^5)^4 = (x^2)^4 / (y^5)^4 = x^8 / y^20

5) (3x + 5y)(4x − 3y) = 12x^2 − 9xy + 20xy − 15y^2 = 12x^2 + 11xy − 15y^2

6) (3x^3y^4z^4)(2x^3y^4z^2) = (3*2) x^(3+3) y^(4+4) z^(4+2) = 6 x^6 y^8 z^6

7) 5x + 3x^4 − 7x^3 ----> Fourth degree trinomial

8) (5x^3 − 5x − 8) + (2x^3 + 4x + 2) = 7x^3 − x − 6

9) (x − 1) + (2x + 5) − (x + 3) = x + 1

10) (−4g^8h^5k^2)0(hk^2)^2 = 0 (anything multiplied by 0 = 0)
or.. (−4g^8h^5k^2)^0(hk^2)^2 = 1 (h^2 (k^2)^2) = h^2 k^4

Last question shows why it is so important to use proper symbols (such as ^ to indicate exponents). Without such symbols, I could not tell if the 0 was an actual number and part of multiplication, of if 0 was an exponent of the expression preceding it.


P.S

Glad to help you have an AWESOME!!! day :)
</span>
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