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Andru [333]
2 years ago
11

Which statements accurately describe how to determine the y-intercept and the slope from the graph below?

Mathematics
2 answers:
fgiga [73]2 years ago
5 0

Answer:

The third option.

Nikitich [7]2 years ago
4 0

Answer:

C.

Step-by-step explanation:

You would start at the origin and move vertically (up and down) to find the y-intercept

The correct formula to find slope is

y2 - y1

_____

x2 - x1

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Which equation is equivalent to the given equation?
adelina 88 [10]

Answer:

B

Step-by-step explanation:

7m+11= -4 x 2m + (-4 x 3)

7m +11 = -8m -12

7m +8m = -12-11

15m = -23

6 0
3 years ago
Mark is going to an awards dinner and wants to dress appropriately. He had one blue shirt, one white dress shirt, one black dres
lidiya [134]

Answer:

<u>All the four statements are true , which are -</u>

(A) The subset contains contains of all the outfits that have grey slacks .

(B)  The subset contains contains of all the outfits that have grey slacks and red tie .

(C) The subset contains contains of all the outfits that have grey slacks and blue shirt .

(D)  The subset contains contains of all the outfits that do not have black slacks .

Step-by-step explanation:

<u>We are given with Outfit 2 , 4 and 6</u>

Outfit 2 -   Blue     grey     red

Outfit 4 -   White    grey     red

Outfit 6   - Black     grey    red

(A) Since only 2,4, and 6 contain grey slacks, and no other outfit contains grey slacks, those are the subsets that contain grey slacks. Thus , this statement is true .

(B) Just outfits 2, 4, and 6 have grey slacks and a red tie, proving the statement. Other clothes do not include grey slacks and a red tie; they may include a red tie but not both grey slacks and a red tie. Hence , the statement is true .

(C) Since the outfit 2 has grey slacks and a blue shirt, the statement is correct; no other outfit has both grey slacks and a blue shirt. Therefore , this statement is also correct .

(D) The argument is correct since all of the subsets contain grey slacks and no black slacks.

Hence , all the options A , B , C , D are correct and describes the subset .

<u>The given question is incomplete , the complete question is attached here - </u>

3 0
3 years ago
Help plz need asap!!
Otrada [13]
For the first question, x = 4
6 0
3 years ago
1 point
Margarita [4]

Answer:

35% or 0.35

Step-by-step explanation

If 20 grams is 100%, that means each gram is 5% of the whole. So 7 time 5 is 35.

4 0
3 years ago
For bone density scores that are normally distributed with a mean of 0 and a standard deviation of​ 1, find the percentage of sc
gogolik [260]

Answer:

a) The percentage of bone density scores that are significantly high is 2.28%

b) The percentage of bone density scores that are significantly low is 2.28%

c) The percentage of bone density scores that are not significant is 95.44%

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

a. significantly high​ (or at least 2 standard deviations above the​ mean).

This is 1 subtracted by the pvalue of Z = 2.

Z = 2 has a pvalue of 0.9772

1 - 0.9772 = 0.0228

2.28% of scores are signifcantly high

b. significantly low​ (or at least 2 standard deviations below the​ mean).

pvalue of Z = -2

Z = -2 has a pvalue of 0.0228

2.28% of scores are signicantly low.

c. not significant​ (or less than 2 standard deviations away from the​ mean).

pvalue of Z = 2 subtracted by the pvalue of Z = -2.

Z = 2 has a pvalue of 0.9772

Z = -2 has a pvalue of 0.0228

0.9772 - 0.0228 = 0.9544

95.44% of the scores are not significant

7 0
3 years ago
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