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MariettaO [177]
3 years ago
11

What do I do it is a quiz due in 5 mins

Mathematics
1 answer:
Alexxandr [17]3 years ago
3 0

8 *6= 42 so it gotta be bigger than 42 and 42 divide by 2  is 21  and 42+21= 63 you got your answer.

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1.Which of the following is equivalent to 0.00451
Finger [1]

Answer:

1)4.51×10^-3

2) .00632

Step-by-step explanation:

1.Which of the following is equivalent to 0.00451?

= \frac{451}{100000}

=\frac{4.51}{1000}

=\frac{4.51}{10^3}

= 4.51×10^-3

Therefore the answer is (a)

===================================================================

Which of the following is equivalent to 6.32 x 10-*3?

In order to find the answer to this question you can just put the notation into standard form which means they will be equivalent to each other.

The exponent is negative so you move to the left:

6.32=.00632

=.00632

Therefore 6.32*10^-3 is equivalent too (c) .00632

4 0
3 years ago
Read 2 more answers
Combine like terms -2xy+2xy+3xy
liberstina [14]

Answer:

3xy

Step-by-step explanation:

These terms are all like terms so you can add:

-2xy + 2xy = <em>0xy</em>

Now add 3xy + 0xy: 3xy

3 0
3 years ago
An airplane accelerates down a runway at 3.20 m/s2 for 32.8 s until is finally lifts off the ground. Determine the distance trav
NNADVOKAT [17]
In a physics equation, given a constant acceleration (a, the change in velocity of an object) and time involved (t), you can figure out the distance (S) traveled by using this formula :



S = 1/2 x acceleration(a) x times(t)^2

So in this case, we can compute the distance by supplying the available data into the equation,...



S = 1/2 x 3.2 m/s2 x (32.8s)^2

S = 1721m
6 0
3 years ago
A girl has a dog and a cat together the pets way 28 pounds the dog weighs three times as much as the cat how much does each pet
Nina [5.8K]
I believe the answer is 7 pounds for the cat, and 21 pounds for the dog
3 0
3 years ago
Kite EFGH is inscribed in a rectangle where F and H are midpoints of parallel sides. The area of EFGH is 35 square units. What i
sasho [114]

*see attachment for the figure described

Answer:

5 units

Step-by-step explanation:

==>Given the figure attached below, let where FH and EG intercepted be K.

Since FH are midpoints of parallel lines, KE = KG = x.

Given that the area of the kite EFGH = 35 square units, and we know the length of one of the diagonals = HF = KF + KH = 2 + 5 = 7, we can solve for x using the formula for the area of a kite.

Area of kite = ½ × d1 × d2

Where d1 = KH = 7

d2 = EG = KE + KG = x + x = 2x

Area of kite EFGH = 35

THUS:

35 = ½ × 7 × 2x

35 = 1 × 7 × x

35 = 7x

Divide both sides by 7

35/7 = x

x = 5

4 0
3 years ago
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