Question

If you are good at sequences in math please help I am giving more points

Answer 1

Answer:

-3, -7, -23, -87, -343

Step-by-step explanation:

n = 1

-3

n = 2

4(-3) + 5

-12 + 5

-7

n = 3

4(-7) + 5

-28 + 5

-23

n = 4

4(-23) + 5

-92 + 5

-87

n = 5

4(-87) + 5

-348 + 5

-343

Answer 2

Answer:

-3, -7, -23, -87, and -343

Step-by-step explanation:

Here, we're given that the sequence is $a_n=4a_{n-1}+5$, where n indicates the nth term and n - 1 indicates the (n - 1)th term.

$a_1=-3$, so if we want to find $a_2$, we can say n = 2 and n - 1 = 1:

$a_2=4a_{1}+5=4*(-3)+5=-12+5=-7$

We continue to do this to find $a_3,a_4,$ and $a_5$:

$a_3=4a_{2}+5=4*(-7)+5=-28+5=-23$

$a_4=4a_{3}+5=4*(-23)+5=-92+5=-87$

$a_5=4a_{4}+5=4*(-87)+5=-348+5=-343$

Thus, the first 5 terms in the sequence are:

-3, -7, -23, -87, and -343

Hope this helps!