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3 years ago

Find the difference. (9/4x + 6)-(-5/4x-24)

Mathematics

2 answers:

maxonik [38]3 years ago

6 0

Answer:

7/2x + 30

Step-by-step explanation:

Svetlanka [38]3 years ago

4 0

Answer:

9x/4 + 30 + 5x/4

Step-by-step explanation:

$9x/4 +30 +5x/5$

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One of the questions Rasmussen Reports included on a 2018 survey of 2,500 likely voters asked if the country is headed in right

kap26 [50]

Answer:

Kindly check explanation

Step-by-step explanation:

Given the data:

553 - No

70 - Not Sure

384 - Yes

Total = (553 + 70 + 384) = 1007

Proportion who do think country is headed in the right direction :

P = yes / total = 384/1007 = 0.381

b.) Error margin at 95%

Margin of Error = Zcritical * √p(1-p)/n

1-p = 1 - 0.381 = 0.619

Zcritical at 95% = 1.96

Margin of error = 1.96 * √0.381(0.619)/1007

Margin of error = 0.030

C.)

95% confidence interval for heading in the right direction:

P ± margin of error

P ± 0.030

Lower boundary = 0.381 - 0.030 = 0.351

Upper boundary = 0.381 + 0.030 = 0.411

(0.351 ; 0.411)

D.)

Confidence interval for people who don't think :

P = 553 / 1007 = 0.549

Confidence interval = P ± margin of error

Error margin at 95%

Margin of Error = Zcritical * √p(1-p)/n

1-p = 1 - 0.549 = 0.451

Zcritical at 95% = 1.96

Margin of error = 1.96 * √0.549(0.451)/1007

Margin of error = 0.031

P ± margin of error

P ± 0.031

Lower boundary = 0.549 - 0.031 = 0.518

Upper boundary = 0.549 + 0.031 = 0.580

(0.518 ; 0.580)

E.)

The interval with smaller error margin is ; 0.030 (those who think country is headed in the right direction because sample proportion is farther from .5 / farther from 1)

6 0

3 years ago

HELP !!!! picture is shown GEOMETRY

kenny6666 [7]

The right triangle is also Isosceles. It has two equal angles of 45°.

(hypotenuse)² = 2S²

4 = 2S² => S = √2

Therefore B is the correct answer.

8 0

3 years ago

24% of what number is 12?

vladimir1956 [14]

To get that, you have to multiply the both numbers, which is 24*12=288

6 0

3 years ago

Read 2 more answers

Find the 4 digit code btw its not 5396 or 6935

Sergeeva-Olga [200]

I think it would be 3569 , i’m not sure tho.

6 0

3 years ago

Read 2 more answers

Due to a manufacturing error, two cans of regular soda were accidentally filled with diet soda and placed into a 18-pack. Suppos

crimeas [40]

Answer:

a) There is a 1.21% probability that both contain diet soda.

b) There is a 79.21% probability that both contain diet soda.

c) $P(X = 2)$ is unusual, $P(X = 0)$ is not unusual

d) There is a 19.58% probability that exactly one is diet and exactly one is regular.

Step-by-step explanation:

There are only two possible outcomes. Either the can has diet soda, or it hasn't. So we use the binomial probability distribution.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

In which $C_{n,x}$ is the number of different combinatios of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And $\pi$ is the probability of X happening.

A number of sucesses $x$ is considered unusually low if $P(X \leq x) \leq 0.05$ and unusually high if $P(X \geq x) \geq 0.05$

In this problem, we have that:

Two cans are randomly chosen, so $n = 2$

Two out of 18 cans are filled with diet coke, so $\pi = \frac{2}{18} = 0.11$

a) Determine the probability that both contain diet soda. P(both diet soda)

That is P(X = 2).

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

$P(X = 2) = C_{2,2}(0.11)^{2}(0.89)^{0} = 0.0121$

There is a 1.21% probability that both contain diet soda.

b)Determine the probability that both contain regular soda. P(both regular)

That is P(X = 0).

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

$P(X = 0) = C_{2,0}(0.11)^{0}(0.89)^{2} = 0.7921$

There is a 79.21% probability that both contain diet soda.

c) Would this be unusual?

We have that $P(X = 2)$ is unusual, since $P(X \geq 2) = P(X = 2) = 0.0121 \leq 0.05$

For P(X = 0), it is not unusually high nor unusually low.

d) Determine the probability that exactly one is diet and exactly one is regular. P(one diet and one regular)

That is P(X = 1).

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

$P(X = 1) = C_{2,1}(0.11)^{1}(0.89)^{1} = 0.1958$

There is a 19.58% probability that exactly one is diet and exactly one is regular.

8 0

3 years ago