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kaheart [24]
2 years ago
5

Question on pic up there :)

Mathematics
1 answer:
olchik [2.2K]2 years ago
6 0

Answer:

that non linear I believe, linear is a straight line,and non linear isnt a straight line,just for future problems

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−7=y7 please help me out
Yuri [45]

Answer:

Step-by-step explanation:

y=-1

7 0
2 years ago
Read 2 more answers
Find the unknown side length x. ​
Ganezh [65]

Answer:

x = \sqrt{65}

Step-by-step explanation:

The altitude of the triangle must equal 4 because it is a right triangle with another leg of 3 and a hypotenuse of 5 (reason is due to the pythagorean theorem)

Therefore, the triangle on the right has legs of 4 and 7 and, again, use the phythagorean theorem to find 'x' (the hypotenuse)

4^{2} + 7^{2} = x^{2}

16 + 49 = x^{2}

65 = x^{2}

x = sq rt 65

6 0
2 years ago
The length of a cell phone is 1.41.4 inches and the width is 4.44.4 inches. The company making the cell phone wants to make a ne
4vir4ik [10]

Answer:

vhasbwwsbawajassbjbsjqsbajbjaqbasqqsjbbsbjsbjabjsqbsbjbjsqbjsqbjsqbjsbsjqbjsqbjsjbsqbjsabsqjaqsa

Step-by-step explanation:

swhbwjqnakksjqkjhqkjhskjqhskjshqkjshqkshkshqkjshqkjshqkjshqksjhqkjhqksjhqkjshkqjswhbwjqnakksjqkjhqkjhskjqhskjshqkjshqkshkshqkjshqkjshqkjshqksjhqkjhqksjhqkjshkqjswhbwjqnakksjqkjhqkjhskjqhskjshqkjshqkshkshqkjshqkjshqkjshqksjhqkjhqksjhqkjshkqjswhbwjqnakksjqkjhqkjhskjqhskjshqkjshqkshkshqkjshqkjshqkjshqksjhqkjhqksjhqkjshkqjswhbwjqnakksjqkjhqkjhskjqhskjshqkjshqkshkshqkjshqkjshqkjshqksjhqkjhqksjhqkjshkqjswhbwjqnakksjqkjhqkjhskjqhskjshqkjshqkshkshqkjshqkjshqkjshqksjhqkjhqksjhqkjshkqjswhbwjqnakksjqkjhqkjhskjqhskjshqkjshqkshkshqkjshqkjshqkjshqksjhqkjhqksjhqkjshkqjswhbwjqnakksjqkjhqkjhskjqhskjshqkjshqkshkshqkjshqkjshqkjshqksjhqkjhqksjhqkjshkqjswhbwjqnakksjqkjhqkjhskjqhskjshqkjshqkshkshqkjshqkjshqkjshqksjhqkjhqksjhqkjshkqjswhbwjqnakksjqkjhqkjhskjqhskjshqkjshqkshkshqkjshqkjshqkjshqksjhqkjhqksjhqkjshkqjswhbwjqnakksjqkjhqkjhskjqhskjshqkjshqkshkshqkjshqkjshqkjshqksjhqkjhqksjhqkjshkqjswhbwjqnakksjqkjhqkjhskjqhskjshqkjshqkshkshqkjshqkjshqkjshqksjhqkjhqksjhqkjshkqjswhbwjqnakksjqkjhqkjhskjqhskjshqkjshqkshkshqkjshqkjshqkjshqksjhqkjhqksjhqkjshkqjswhbwjqnakksjqkjhqkjhskjqhskjshqkjshqkshkshqkjshqkjshqkjshqksjhqkjhqksjhqkjshkqjswhbwjqnakksjqkjhqkjhskjqhskjshqkjshqkshkshqkjshqkjshqkjshqksjhqkjhqksjhqkjshkqjswhbwjqnakksjqkjhqkjhskjqhskjshqkjshqkshkshqkjshqkjshqkjshqksjhqkjhqksjhqkjshkqjswhbwjqnakksjqkjhqkjhskjqhskjshqkjshqkshkshqkjshqkjshqkjshqksjhqkjhqksjhqkjshkqjswhbwjqnakksjqkjhqkjhskjqhskjshqkjshqkshkshqkjshqkjshqkjshqksjhqkjhqksjhqkjshkqjswhbwjqnakksjqkjhqkjhskjqhskjshqkjshqkshkshqkjshqkjshqkjshqksjhqkjhqksjhqkjshkqjswhbwjqnakksjqkjhqkjhskjqhskjshqkjshqkshkshqkjshqkjshqkjshqksjhqkjhqksjhqkjshkqjswhbwjqnakksjqkjhqkjhskjqhskjshqkjshqkshkshqkjshqkjshqkjshqksjhqkjhqksjhqkjshkqjswhbwjqnakksjqkjhqkjhskjqhskjshqkjshqkshkshqkjshqkjshqkjshqksjhqkjhqksjhqkjshkqjswhbwjqnakksjqkjhqkjhskjqhskjshqkjshqkshkshqkjshqkjshqkjshqksjhqkjhqksjhqkjshkqjswhbwjqnakksjqkjhqkjhskjqhskjshqkjshqkshkshqkjshqkjshqkjshqksjhqkjhqksjhqkjshkqjswhbwjqnakksjqkjhqkjhskjqhskjshqkjshqkshkshqkjshqkjshqkjshqksjhqkjhqksjhqkjshkqjswhbwjqnakksjqkjhqkjhskjqhskjshqkjshqkshkshqkjshqkjshqkjshqksjhqkjhqksjhqkjshkqjswhbwjqnakksjqkjhqkjhskjqhskjshqkjshqkshkshqkjshqkjshqkjshqksjhqkjhqksjhqkjshkqjswhbwjqnakksjqkjhqkjhskjqhskjshqkjshqkshkshqkjshqkjshqkjshqksjhqkjhqksjhqkjshkqjswhbwjqnakksjqkjhqkjhskjqhskjshqkjshqkshkshqkjshqkjshqkjshqksjhqkjhqksjhqkjshkqjswhbwjqnakksjqkjhqkjhskjqhskjshqkjshqkshkshqkjshqkjshqkjshqksjhqkjhqksjhqkjshkqjswhbwjqnakksjqkjhqkjhskjqhskjshqkjshqkshkshqkjshqkjshqkjshqksjhqkjhqksjhqkjshkqjswhbwjqnakksjqkjhqkjhskjqhskjshqkjshqkshkshqkjshqkjshqkjshqksjhqkjhqksjhqkjshkqjswhbwjqnakksjqkjhqkjhskjqhskjshqkjshqkshkshqkjshqkjshqkjshqksjhqkjhqksjhqkjshkqjswhbwjqnakksjqkjhqkjhskjqhskjshqkjshqkshkshqkjshqkjshqkjshqksjhqkjhqksjhqkjshkqjswhbwjqnakksjqkjhqkjhskjqhskjshqkjshqkshkshqkjshqkjshqkjshqksjhqkjhqksjhqkjshkqjswhbwjqnakksjqkjhqkjhskjqhskjshqkjshqkshkshqkjshqkjshqkjshqksjhqkjhqksjhqkjshkqjswhbwjqnakksjqkjhqkjhskjqhskjshqkjshqkshkshqkjshqkjshqkjshqksjhqkjhqksjhqkjshkqjswhbwjqnakksjqkjhqkjhskjqhskjshqkjshqkshkshqkjshqkjshqkjshqksjhqkjhqksjhqkjshkqjswhbwjqnakksjqkjhqkjhskjqhskjshqkjshqkshkshqkjshqkjshqkjshqksjhqkjhqksjhqkjshkqjswhbwjqnakksjqkjhqkjhskjqhskjshqkjshqkshkshqkjshqkjshqkjshqksjhqkjhqksjhqkjshkqjswhbwjqnakksjqkjhqkjhskjqhskjshqkjshqkshkshqkjshqkjshqkjshqksjhqkjhqksjhq

7 0
3 years ago
The equation of the parabola whose focus is at (7 0) and directrix at y=-7 is
bija089 [108]
The equation of the parabola whose focus is at (7, 0) and directrix at y = -7 is 
(x-7)^2 = 14(y + 7/2)

Hope this helps
5 0
3 years ago
Find the length BC
Nady [450]
Answer:

The length of BC = 12

Step-by-step explanation:

c^2 = a^2 + b^2

15^2 = 9^2 + b^2

225 = 81 + b^2

b^2 = 225 - 81

b^2 = 144

b = 12

The length of BC is 12
5 0
3 years ago
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