For the first one,
you multiply 5x and -5 to get -25.
Then you move the constant to the right and change the sign to get 3x= -21 +25.
Calculate the sum of -21+25 to get 4.
Divide both sides of the equation by 3 to get x=4/3.
So then your final answer is x=4
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3
For the second one,
Distribute 7 through the parentheses to get 14x + 14+8=120
The you add 14+8 to get 22. Your equation should be 14x+22=120
Move the constant to the right side and change its sign to get 14x=120-22
Subtract 120-22 to get 98. Now your equation should be 14x=98
Divide both sides of the equation by 14 to get x=7.
Your finial answer for the second one should be x=7.
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I hope this made sense.
<h3>
Answer: 1/8</h3>
In decimal form, 1/8 = 0.125 which converts to 12.5%
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Work Shown:
The 63 should be 6^3. There are 6 choices per slot, and 3 slots, so 6^3 = 216 different outcomes.
Here are all of the ways to add to 11 if we had 3 dice
- sum = 1+4+6 = 11
- sum = 1+5+5 = 11
- sum = 1+6+4 = 11
- sum = 2+3+6 = 11
- sum = 2+4+5 = 11
- sum = 2+5+4 = 11
- sum = 2+6+3 = 11
- sum = 3+2+6 = 11
- sum = 3+3+5 = 11
- sum = 3+4+4 = 11
- sum = 3+5+3 = 11
- sum = 3+6+2 = 11
- sum = 4+1+6 = 11
- sum = 4+2+5 = 11
- sum = 4+3+4 = 11
- sum = 4+4+3 = 11
- sum = 4+5+2 = 11
- sum = 4+6+1 = 11
- sum = 5+1+5 = 11
- sum = 5+2+4 = 11
- sum = 5+3+3 = 11
- sum = 5+4+2 = 11
- sum = 5+5+1 = 11
- sum = 6+1+4 = 11
- sum = 6+2+3 = 11
- sum = 6+3+2 = 11
- sum = 6+4+1 = 11
There are 27 ways to add to 11 using 3 dice. This is out of 216 total outcomes of 3 dice being rolled.
So, 27/216 = (1*27)/(8*27) = 1/8 is the probability of getting 3 dice to add to 11.
Hello,
aPb=b*(b-1)*(b-2)*....*(b-a+1) / a!
3P5=5*4*3/(3*2*1)=10
If we name the number of the employers 1,2,3,4,5
Here are the choices:
123,124,125,134,135,145,234,235,245,345 (total 10 choices)
