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3 years ago

Can someone pls solve this

Mathematics

2 answers:

vredina [299]3 years ago

8 0

Answer:

G=23/16

Step-by-step explanation:

EleoNora [17]3 years ago

5 0

23/16 or in decimal form 1.4375. Firyou’d add -5/4 to 3/16.

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Rachel’s free-throw average for basketball is 60%. Describe how you can use 10 index cards to model this situation. Then use a s

Thepotemich [5.8K]

1. If Rachel's free-throw percentage is 60%, you can take 4 index cards away since 100 - 40 = 60%. For example, if those 10 index cards represent 10 free-throws, and her percentage is 60%, just take 60 away from the total (100%).

2. For the simulation, it's the same as problem 1. Since 50 is the total amount of shots she is going to take, and you know she is going make 60% of them, take 60% from 50 which gives you 30. That means she will make 30 of them and miss 20 of them

I hoped I helped

X8lue83rryX

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3 years ago

Read the proof.

Eva8 [605]

Answer:

Its B kiddos

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Given that z is a standard normal random variable, find z for each situation. The area to the right of z is .1314. (Round to two

Mumz [18]

Answer:

$P(Z>0.1314) = 1-P(Z$

We can use the following excel code: "=1-NORM.DIST(0.1314,0,1,TRUE)" or the standard normal table

$P(Z$

We can use the following excel code: "=NORM.DIST(0.75,0,1,TRUE)" or the standard normal table.

$P(Z>0.01) = 1-P(Z$

We can use the following excel code: "=1-NORM.DIST(0.01,0,1,TRUE)" or the standard normal table

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Solution to the problem

$P(Z>0.1314) = 1-P(Z$

We can use the following excel code: "=1-NORM.DIST(0.1314,0,1,TRUE)" or the standard normal table

$P(Z$

We can use the following excel code: "=NORM.DIST(0.75,0,1,TRUE)" or the standard normal table.

$P(Z>0.01) = 1-P(Z$

We can use the following excel code: "=1-NORM.DIST(0.01,0,1,TRUE)" or the standard normal table

6 0

4 years ago

I NEED HELP PLEASE!!

Sergio039 [100]

Answer:

9 units because eqidistance from center

8 0

3 years ago

A test contains 40 questions Max's goal is to learn at least a 90 percent how many questions must he answer correctly to get at

Mice21 [21]

90% = 90/100

x/40=90/100 cross multiply

100x = 3600 divide by 100 on both sides
x=36

Max needs to get at least 36 questions correct to earn a 90&

6 0

3 years ago