Y2-y1\x2-x1
0-6/5-4
(-6,1) and
-10+4/-2+3
(-6,1)
Answer:

Step-by-step explanation:
a is the height
b is the base
c is the hypotenuse
The area of the disk is approximately 314 inches
You see how these 2 angles marked are both inside the 2 parallel lines?
And they are on opposite side of the transversal, the line crossing the 2 parallel lines?
These 2 angles are alternate interior angles and they are equal, I think you can do the last part by yourself.

From a point Q, the length of the tangent to a circle is 24 cm and the distance of Q from the centre is 25 cm find the radius of the circle.

Here, O is the center of the circle.
<u>⟼</u><u> </u><u>Given</u><u> </u><u>:</u>
<u>⟼</u><u> </u><u>To</u><u> </u><u>Find</u><u> </u><u>:</u><u> </u> We have to find the radius OP.
Since QP is tangent, OP perpendicular to QP.
(Since, Tangent is Perpendicular to Radius ⠀⠀⠀⠀⠀⠀⠀at the point of contact)
So, ∠OPQ=90°
<u>⟼</u><u> </u><u>By</u><u> </u><u>Applying</u><u> </u><u>Pythagoras</u><u> </u><u>Theorem</u><u> </u><u>:</u>
OP² + RQ² = OQ²
OP² + (24)² = (25)²
OP² = 625 - 576
OP² = 49
OP = √49
<u>OP</u><u> </u><u>=</u><u> </u><u>7</u><u> </u><u>cm</u>
<u>Hence</u><u>,</u><u> </u><u>The</u><u> </u><u>Radius</u><u> </u><u>is</u><u> </u><u>7</u><u> </u><u>cm</u>
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<h3>-MissAbhi</h3>