0.4 and 0.4 or 0.8 and 0.2
Hope this helps :)
I’m pretty sure it’s linear!
Answer:
Choice A) .
Step-by-step explanation:
What are the changes that would bring to ?
- Translate to the left by unit, and
- Stretch vertically (by a factor greater than .)
. The choices of listed here are related to :
- Choice A) ;
- Choice B) ;
- Choice C) ;
- Choice D) .
The expression in the braces (for example as in ) is the independent variable.
To shift a function on a cartesian plane to the left by units, add to its independent variable. Think about how , which is to the left of , will yield the same function value.
Conversely, to shift a function on a cartesian plane to the right by units, subtract from its independent variable.
For example, is unit to the left of . Conversely, is unit to the right of . The new function is to the left of . Meaning that should should add to (rather than subtract from) the independent variable of . That rules out choice B) and D).
- Multiplying a function by a number that is greater than one will stretch its graph vertically.
- Multiplying a function by a number that is between zero and one will compress its graph vertically.
- Multiplying a function by a number that is between and zero will flip its graph about the -axis. Doing so will also compress the graph vertically.
- Multiplying a function by a number that is less than will flip its graph about the -axis. Doing so will also stretch the graph vertically.
The graph of is stretched vertically. However, similarly to the graph of this graph , the graph of increases as increases. In other words, the graph of isn't flipped about the -axis. should have been multiplied by a number that is greater than one. That rules out choice C) and D).
Overall, only choice A) meets the requirements.
Since the plot in the question also came with a couple of gridlines, see if the points 's that are on the graph of fit into the expression .
Answer:
and
Step-by-step explanation:
Given
See attachment for complete question
Required
Determine the equilibrium solutions
We have:
To solve this, we first equate and to 0.
So, we have:
Factor out R in
Split
or
or
Factor out W in
Split
or
Solve for R
Make R the subject
When , we have:
Collect like terms
Solve for W
When , we have:
Collect like terms
Solve for R
So, we have:
When , we have:
So, we have:
Hence, the points of equilibrium are:
and