The length of the diagonal AB of the given square is 8.660
Given that a diagram of a cube having dimensions 5×5×5 and asked to find out the length of diagonal AB(which is a body diagonal of the cube).
To calculate the body diagonal 1st we need to calculate the face diagonal via the Pythagorean theorem
Let's assume the length of the face diagonal is x
By Pythagorean theorem
Therefore, the length of the face diagonal is
Let's assume the body diagonal is y
By Pythagorean theorem
y==8.660
Therefore, The length of the diagonal AB of the given square is 8.660
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13+3k=11
-Move constant to the right-hand side and change its sign
3k=11-13
Calculate the difference
3k=-2
Divide both sides by 3
K= -2/3
I would need see what your choices are to give exact answers, but I think the main idea here is to see that angles 1 and 3 are the same, and since the alternate interior angle theorem states parallel lines through a line, or another set of parallel lines, form equal angles on those positions, the lines that form those angles, p and q, must be parallel.