Damage to the __________ will result in the loss of ability to hear certain frequencies.

1 answer:

5 0

Ear drum because if damaged it can cause pain and loss of hearing to certain degrees.

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Gnom [1K]

Answer:

The answer is below

Explanation:

1. People often postpone dying until they've "said goodbye to their loved ones."

2. The activities involving nature that could help someone who is grieving is "Taking a walk in the woods."

3. Some things a young person should know before visiting a dying friend or relative in the hospital are:

* The dying relative may die at any time during or immediately after their visit

* Be ready for a change of plans at any moment

* Be ready to handle silence

* Have something to say about shared memories

* Come with treats

4. Alzheimer: this is a type of disease associated with loss of memory and it is a common cause of Dementia

5. Grieving people need love and support most.

6. Some of the things research found out about contentment in the elderly compared to young adults are:

* Older people derive happiness in small things

* They value meaningful relationships

* They easily volunteer

5 0

3 years ago

statuscvo [17]

Answer:

$\displaystyle y' = (1 + x)^2(4x + 1)$

General Formulas and Concepts:

Algebra I

Calculus

Derivatives

Derivative Notation

Derivative Property [Addition/Subtraction]: $\displaystyle \frac{d}{dx}[f(x) + g(x)] = \frac{d}{dx}[f(x)] + \frac{d}{dx}[g(x)]$

Basic Power Rule:

Derivative Rule [Product Rule]: $\displaystyle \frac{d}{dx} [f(x)g(x)]=f'(x)g(x) + g'(x)f(x)$

Derivative Rule [Chain Rule]: $\displaystyle \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)$

Explanation:

Step 1: Define

Identify

y = x(1 + x)³

Step 2: Differentiate

Product Rule [Derivative Rule - Chain Rule]: $\displaystyle y' = \frac{d}{dx}[x] \cdot (1 + x)^3 + x \cdot \frac{d}{dx}[(1 + x)^3] \cdot \frac{d}{dx}[1 + x]$
Derivative Property [Addition/Subtraction]: $\displaystyle y' = \frac{d}{dx}[x] \cdot (1 + x)^3 + x \cdot \frac{d}{dx}[(1 + x)^3] \cdot (\frac{d}{dx}[1] + \frac{d}{dx}[x])$
Basic Power Rule: $\displaystyle y' = x^{1 - 1} \cdot (1 + x)^3 + x \cdot 3(1 + x)^{3 - 1} \cdot (0 + x^{1 - 1})$
Simplify: $\displaystyle y' = (1 + x)^3 + 3x(1 + x)^2$
Factor: $\displaystyle y' = (1 + x)^2 \bigg[ (1 + x) + 3x \bigg]$
Combine like terms: $\displaystyle y' = (1 + x)^2(4x + 1)$