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frosja888 [35]
3 years ago
8

Pls help my semester end today and I have ds

Mathematics
1 answer:
dsp733 years ago
6 0

Answer:

4.125 I believe.

Step-by-step explanation:

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The shark are fed three times a day during the morning feeding 2/15 of a ton. During the afternoon feeding the weight of fish fe
UNO [17]

Answer:

The shark are fed \frac16 \ ton of fish during the night.

Step-by-step explanation:

Given:

Weight of fish fed in the morning = \frac{2}{15}\ ton

Also Given:

During the afternoon feeding the weight of fish fed will be 1/15 of a ton more than the fish fed during the morning.

Weight of fish fed in the afternoon = \frac{2}{15}+\frac{1}{15}=\frac{2+1}{15}=\frac{3}{15}\ ton

Total fish fed in whole day = \frac12 \ ton

We need to find the Weight of fish fed in the night.

Solution:

Now we can say that;

Weight of fish fed in the night can be calculated by by subtracting Weight of fish fed in the morning and Weight of fish fed in the afternoon from Total fish fed in whole day .

framing in equation form we get;

Weight of fish fed in the night = \frac{1}{2}-\frac{2}{15}-\frac{3}{15}= \frac{1}{2}-(\frac{2}{15}+\frac{3}{15})=\frac{1}{2}-\frac{2+3}{15}= \frac{1}{2}-\frac{5}{15} = \frac{1}{2}-\frac{1}{3}

Now we will use LCM for making the denominator common we get;

Weight of fish fed in the night = \frac{1\times3}{2\times3}-\frac{1\times2}{3\times2} = \frac{3}{6}-\frac{2}{6}

Now denominator are common so we will solve the numerators.

Weight of fish fed in the night = \frac{3-2}{6}=\frac16 \ ton

Hence The shark are fed \frac16 \ ton of fish during the night.

3 0
3 years ago
In this triangle, the product of sin Band tan cis<br> and the product of sin cand tan is
Alborosie

Answer:

In this triangle, the product of sin B and tan C is c/a or cos B, and the product of sin C and tan B is b/a cos C. We determine these as follows:

sin B tan C = b/a (c/b) = c/a

sin C tan B = c/a (b/c) = b/a

Hope this answers the question. Have a nice day.

Step-by-step explanation:

DONT NOW AM NO SURE

8 0
3 years ago
Find m/AEB<br><br> A.<br> 10<br> B.<br> 70<br> C.<br> 110<br> D.<br> 170
Paul [167]
A is most likely the answer.

Hope this Helped!

;D
5 0
4 years ago
Read 2 more answers
An element with mass 780 grams decays by 16.3% per minute. How much of the element is remaining after 16 minutes, to the nearest
vitfil [10]
Exponential decay is a very common process especially when we are talking about radioactive materials. So, there is already a common formula for this type of behavior which is written below:

A = Pe^-rt
where
A is the amount left after time t
P is the initial amount at t=0
r is the rate

Substituting the values,
A = (780 g)(e^-0.163*16)
A = 57.5 g
8 0
4 years ago
Evaluate the following expressions:<br> 1. 5(a+2b)-3b
Alika [10]

Answer:

=5a+7b

Step-by-step explanation:

Expand: 5(a + 2b): 5a + 10b
=5a+10b-3b
<em>Add similar elements: 10b-3b=7b
</em>=5a +7b

4 0
2 years ago
Read 2 more answers
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