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Anvisha [2.4K]
3 years ago
6

25 1/2 × 8 4/3 =........

Mathematics
1 answer:
tatiyna3 years ago
5 0
D. 200
yaaaaaaaa
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I need help the question is what is the are of the composite figure
AlladinOne [14]

Answer:

Option 4

Step-by-step explanation:

Area of a trapezoid = \frac{1}{2}(b_1+b_2)h

Here, b_1 and b_2 are the bases and 'h' is the height between the bases.

Area of the composite figure = Area of two trapezoids given

                                                = \frac{1}{2}(12+12)14+\frac{1}{2}(25+31)11

                                                = \frac{1}{2}(24)(14)+\frac{1}{2}(56)(11)

                                                = 168 + 308

                                                = 476 square ft

Option 4 is the answer.

3 0
3 years ago
May I please have the answers to this problem​
sp2606 [1]

Answer:

6x+5

Step-by-step explanation:

2x+4x =6x

10-5=5

6x+5

6 0
3 years ago
A new test to detect TB has been designed. It is estimated that 88% of people taking this test have the disease. The test detect
Elodia [21]

Answer:

Correct option: (a) 0.1452

Step-by-step explanation:

The new test designed for detecting TB is being analysed.

Denote the events as follows:

<em>D</em> = a person has the disease

<em>X</em> = the test is positive.

The information provided is:

P(D)=0.88\\P(X|D)=0.97\\P(X^{c}|D^{c})=0.99

Compute the probability that a person does not have the disease as follows:

P(D^{c})=1-P(D)=1-0.88=0.12

The probability of a person not having the disease is 0.12.

Compute the probability that a randomly selected person is tested negative but does have the disease as follows:

P(X^{c}\cap D)=P(X^{c}|D)P(D)\\=[1-P(X|D)]\times P(D)\\=[1-0.97]\times 0.88\\=0.03\times 0.88\\=0.0264

Compute the probability that a randomly selected person is tested negative but does not have the disease as follows:

P(X^{c}\cap D^{c})=P(X^{c}|D^{c})P(D^{c})\\=[1-P(X|D)]\times{1- P(D)]\\=0.99\times 0.12\\=0.1188

Compute the probability that a randomly selected person is tested negative  as follows:

P(X^{c})=P(X^{c}\cap D)+P(X^{c}\cap D^{c})

           =0.0264+0.1188\\=0.1452

Thus, the probability of the test indicating that the person does not have the disease is 0.1452.

4 0
3 years ago
What is the positive slope of the asymptote of the hyperbola?The positive slope of the asymptote is
SVETLANKA909090 [29]

Answer:

1

Step-by-step explanation:

on edge

7 0
3 years ago
What is the distance between the points (-5, 10) and (-5, 2)?
Alona [7]
8 units hope I helped
7 0
3 years ago
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