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Verizon [17]
3 years ago
5

From 5 a.m. to noon, the temperature rose 15 °F to a high of 10 °F.

Mathematics
1 answer:
kodGreya [7K]3 years ago
7 0

Answer:

The temperature was 5 °F

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If f(x)=x^2 what is g(x)<br> A. g(x)=1/9x^2<br> B. g(x)=(1/3x)^2<br> C. g(x)=3x^2<br> D. g(x)=1/3x^2
Pavlova-9 [17]

Answer:

the answer is B

Step-by-step explanation:

3 0
3 years ago
micheal brought 12 used books at th book sale. he paid $42.60 for the books. if each book cost the same price, how much did one
nordsb [41]

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Each book cost $3.55

Step-by-step explanation:

3 0
2 years ago
What is the base, perimeter of base, and height of this figure? No links pls or I will report u!
prisoha [69]
The base is 315. Perimeter of base is 72.
5 0
2 years ago
Derek wants to construct a square box stall for each horse that is to be housed in a stable. He wants all of the box stalls to h
ale4655 [162]
The total area of the stable is 20,250 sq. ft.

Let n = total number of box stalls.

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Therefore
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8 0
3 years ago
Find and compare the growth rates in the weekly number of specialty items produced at each factory.
DerKrebs [107]

0.129 is the change in the growth rate of company.

According to statement

we have to find and compare the growth rate of the company weekly.

we use the growth rate formula is

GROWTH RATE = present - past / present

Substitute the values in this formula

1st week = 220-190 / 220

1st week = 0.136

2nd week = 252-220 / 252

2nd week = 32 / 252

2nd week = 0.126

3rd week = 290-252 / 290

3rd week = 0.131

4th week = 337 - 290 / 337

4th week = 0.139

5th week = 380 - 337 / 380

5th week = 0.113

6th week = 440 - 380 / 440

6th week = 0.136

7th week = 505 - 440 / 505

7th week = 0.128

Now we find the average value of growth rate

Average = 0.136 + 0.126+0.131+0.139+0.113+0.136+0.128 /7

Average = 0.909/7

Average = 0.129

So, 0.129 is the change in the growth rate of company.

Learn more about GROWTH RATE here brainly.com/question/20115298

#SPJ1

7 0
2 years ago
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