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Verizon [17]
3 years ago
5

From 5 a.m. to noon, the temperature rose 15 °F to a high of 10 °F.

Mathematics
1 answer:
kodGreya [7K]3 years ago
7 0

Answer:

The temperature was 5 °F

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airplane is flying from New York City to Los Angeles the distant it travels in miles is related to the time in seconds by the eq
givi [52]
Incomplete question. Please share complete question
7 0
3 years ago
Please answer this question now
Nataly [62]

Answer:

<h2>S = 11.4</h2>

Step-by-step explanation:

To find s we use the cosine rule

That's

s² = SU² + ST² - 2(SU)(ST) cos S

From the question

SU = 5

ST = 13

S = 60°

Substituting the values into the expression we have

s² = 5² + 13² - 2(5)(13) cos 60

s² = 25 + 169 - 130cos 60

s² = 194 - 65

s² = 129

Find the square root of both sides

s= √129

s = 11.357816

We have the final answer as

<h3>s = 11.4 to the nearest tenth</h3>

Hope this helps you

3 0
3 years ago
GIVING BRAINLIEST!
statuscvo [17]

Answer:b

Step-by-step explanation:

8 0
2 years ago
Claire Judice
Julli [10]

Answer:

The values of 'x' are -1.2, 0, 0, -4i or 4i.

Step-by-step explanation:

Given:

The equation to solve is given as:

5x^5+6x^4+80x^3+96x^2=0

Factoring x^2 from all the terms, we get:

x^2(5x^3+6x^2+80x+96)=0

Now, rearranging the terms, we get:

x^2(5x^3+80x+6x^2+96)=0

Now, factoring 5x from the first two terms and 6 from the last two terms, we get:

x^2(5x(x^2+16)+6(x^2+16))=0\\x^2(x^2+16)(5x+6)=0

Now, equating each factor to 0 and solving for 'x', we get:

x^2=0\\x=0\ and\ 0\\\\5x+6=0\\x=\frac{-6}{5}=1.2\\\\x^2+16=0\\x^2=-16\\x=\sqrt{-16}=\pm 4i

There are 3 real values and 2 imaginary values. The value of 'x' as 0 is repeated twice.

Therefore, the values of 'x' are -1.2, 0, 0, -4i or 4i.

4 0
3 years ago
Which equation can be used to find the surface area of the cylinder?
ki77a [65]

Step-by-step explanation:

Surface Area of the Cylinder

= 2πr² + 2πrh

r = 4 in

h = 16 in

Surface Area :

= 2πr² + 2πrh

= 2π (4)² + 2π (4) (16)

<em>Hope </em><em>it </em><em>helpful </em><em>and </em><em>useful </em><em>:</em><em>)</em>

6 0
3 years ago
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