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DENIUS [597]
3 years ago
7

At a neighborhood picnic, the kids found a long rope and had a tug of war. one side had twice as many kids as the other side, so

three adults helped out the side with fewer kids. With the adults, that side had a total of 11 people. How many kids were on the other side?
Mathematics
2 answers:
Ipatiy [6.2K]3 years ago
7 0

Answer:

16 children

Step-by-step explanation:

If you do:

11-3=8

8×2=16

I hope you understood

vfiekz [6]3 years ago
6 0
Hey there!


On the one side that had more kids, it had 16 kids.


Work:

11 - 3(Adults) = 8(Kids left)

Twice as many without the adults

8 x 2 = 16


Hope I was able to help!
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Bonita is testing prototype model rocket engines. To be considered a successful launch, the rocket must reach a height of at lea
lbvjy [14]

Answer:

(0, 33)   : Yes

(4.8,  30.5)  : Yes


Step-by-step explanation:

height of at least 24 ft :  y >= 24

horizontal distance of no more than 10 ft. : 0 <= x <= 10

The vertical height must be at least three times as high as the horizontal distance. No rocket should go higher than 33 ft.:

y >=  3x and y <= 33

So Constraints:

24 <= y <= 33

y >= 3x

0 <= x <= 10

Now check to see if those coordinate points meet all the constraints

(0, 33)   : Yes

(4.8, 30.5)  : Yes

(9, 26)  : No (because 26 is less than (3 * 9) = 27)

(4, 36) : No (because 36 > 33,  must be 24 <= y <= 33)

(2, 22): No (because 22 <24,  must be 24 <= y <= 33)

5 0
3 years ago
What is £56 divided in a ratio of 3:5?
Luda [366]
First, add the ratio together to get the denominator of the fraction you will use to determine the share. 3+5= 8. Now, you have two fractions: 3/8 and 5/8. Next, just find 3/8 and 5/8 of 56 to get your answers:
(56÷8)×3= <span>£21
</span>and
(56÷8)×5= <span>£35</span>
7 0
3 years ago
The length of a 200 square foot rectangular vegetable garden is 4feet less than twice the width. Find the length and width of th
inna [77]

Answer:

Length = 18.099 ft

Width = 11.049 ft

Step-by-step explanation:

let the length of the field be x ft

and the width be y ft

as per the condition given in problem

x=2y-4   -----------(A)

Also the area is given as 200 sqft

Hence

xy=200

Hence from A we get

y(2y-4)=200

taking 2 as GCF out

2y(y-2)=200

Dividing both sides by 2 we get

y(y-2)=100

y^2-2y=100

subtracting 100 from both sides

y^2-2y-100=0

Now we solve the above equation with the help of Quadratic formula which is given in the image attached with this for any equation in form

ax^2+bx+c=0

Here in our case

a=1

b=-1

c=-100

Putting those values in the formula and solving them for y

y=\frac{-(-2)+\sqrt{(-2)^2-4 \times (-1) \times 100}}{2 \time 1}

y=\frac{-(-2)-\sqrt{(-2)^2-4 \times (-1) \times 100}}{2 \time 1}

Solving first

y=\frac{2+\sqrt{4+400}{2}

y=\frac{2+\sqrt{404}{2}

y=\frac{2+20.099}{2}

y=\frac{22.099}{2}

y=11.049

Solving second one

y=\frac{-(-2)-\sqrt{(-2)^2-4 \times (-1) \times 100}}{2 \time 1}

y=\frac{2-\sqrt{4+400}{2}

y=\frac{2-\sqrt{404}{2}

y=\frac{2-20.099}{2}

y=\frac{-18.99}{2}

y=-9.045

Which is wrong as the width can not be in negative

Our width of the field is

y=11.099

Hence the length will be

x=2y-4

x=2(11.049)-4

x=22.099-4

x=18.099

Hence our length x and width y :

Length = 18.099 ft

Width = 11.049 ft

4 0
3 years ago
PLEASE HELP ILL MARK BRAINEST!!!!
earnstyle [38]

Answer:

(-3,8) would NOT fit the table.

6 0
2 years ago
Read 2 more answers
**CLICK PHOTO TO SEE FULL QUESTION**<br>Does anyone know how it works and the answer?
Nookie1986 [14]
3(the fee per hour) * 5(the number of hours) = 15
15 + 10(the initial fee) = 25
The answer is true.
3 0
3 years ago
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