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Mariana [72]
2 years ago
7

A jacket at the store is being offered at a 30% discount. If the original price of the jacket is x, which answer choice shows an

expression that represents the discounted price of the jacket?
Please answer quickly :(
Mathematics
1 answer:
kifflom [539]2 years ago
6 0

Answer:

x-.30(x)

Step-by-step explanation:

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Assume for Namibia that the opportunity cost of each hut is 200 bowls. Then which of these pairs of points could be on Namibia's
Vaselesa [24]

The pairs that would be on Namibia's production possibilities frontier are (200 huts, 40,000 bowls) and (150 huts, 30,000 bowls) (option B).

<h3>What are the pairs on the possibilities frontier?</h3>

The Production possibilities frontiers is a curve that shows the various combination of two goods a company can produce when all its resources are fully utilised.

The PPC is concave to the origin. This means that as more quantities of a product is produced, the fewer resources it has available to produce another good.

Opportunity cost of the next best option forgone when one alternative is chosen over other alternatives. The pairs that would be on the frontier are the options that have an opportunity cost of 200 bowls when 1 hut is produced.

Opportunity cost of these pairs: (200 huts, 40,000 bowls) and (150 huts, 30,000 bowls)

  • Opportunity cost = 40,000 / 200 = 200
  • Opportunity cost = 30,000 / 150 = 200

Here is the complete question:
Assume for Namibia that the opportunity cost of each hut is 200 bowls. Which of these pairs of points could be on Namibia's production possibilities frontier?

a. (200 huts, 30,000 bowls) and (150 huts, 35,000 bowls)

b. (200 huts, 40,000 bowls) and (150 huts, 30,000 bowls)

c. (300 huts, 50,000 bowl) and (200 huts, 60,000 bowls)

d. (300 huts, 60,000 bowls) and (200 huts, 80,000 bowls)

To learn more about opportunity cost, please check: brainly.com/question/26315727

#SPJ1

6 0
1 year ago
Can someone hurry help me
Dmitriy789 [7]

Answer:

Function, in mathematics, an expression, rule, or law that defines a relationship between one variable (the independent variable) and another variable (the dependent variable). Functions are ubiquitous in mathematics and are essential for formulating physical relationships in the sciences.As we have seen in examples above, we can represent a function using a graph. Graphs display many input-output pairs in a small space. ... The most common graphs name the input value x and the output value y , and we say y is a function of x , or y=f(x) y = f ( x ) when the function is named f .

Step-by-step explanation:

Brainlist will be very accept if you want took me a while to do :)

7 0
3 years ago
algebra i accedently clicked da last question but is it right? which one the correct one pls ill love u foreverrr
Elden [556K]

Answer:

Number 3

Step-by-step explanation:

3 0
2 years ago
4. Using the geometric sum formulas, evaluate each of the following sums and express your answer in Cartesian form.
nikitadnepr [17]

Answer:

\sum_{n=0}^9cos(\frac{\pi n}{2})=1

\sum_{k=0}^{N-1}e^{\frac{i2\pi kk}{2}}=0

\sum_{n=0}^\infty (\frac{1}{2})^n cos(\frac{\pi n}{2})=\frac{1}{2}

Step-by-step explanation:

\sum_{n=0}^9cos(\frac{\pi n}{2})=\frac{1}{2}(\sum_{n=0}^9 (e^{\frac{i\pi n}{2}}+ e^{\frac{i\pi n}{2}}))

=\frac{1}{2}(\frac{1-e^{\frac{10i\pi}{2}}}{1-e^{\frac{i\pi}{2}}}+\frac{1-e^{-\frac{10i\pi}{2}}}{1-e^{-\frac{i\pi}{2}}})

=\frac{1}{2}(\frac{1+1}{1-i}+\frac{1+1}{1+i})=1

2nd

\sum_{k=0}^{N-1}e^{\frac{i2\pi kk}{2}}=\frac{1-e^{\frac{i2\pi N}{N}}}{1-e^{\frac{i2\pi}{N}}}

=\frac{1-1}{1-e^{\frac{i2\pi}{N}}}=0

3th

\sum_{n=0}^\infty (\frac{1}{2})^n cos(\frac{\pi n}{2})==\frac{1}{2}(\sum_{n=0}^\infty ((\frac{e^{\frac{i\pi n}{2}}}{2})^n+ (\frac{e^{-\frac{i\pi n}{2}}}{2})^n))

=\frac{1}{2}(\frac{1-0}{1-i}+\frac{1-0}{1+i})=\frac{1}{2}

What we use?

We use that

e^{i\pi n}=cos(\pi n)+i sin(\pi n)

and

\sum_{n=0}^k r^k=\frac{1-r^{k+1}}{1-r}

6 0
3 years ago
find the product with the exponent in the simplest form. Then, identify the values of x and y. 6^1/3 * 6^1/4 = 6^x/y
mr Goodwill [35]
<span>6^1/3 * 6^1/4 = 6^x/y

The key to solving this problem is understanding properties of exponents:
If you are multiplying two powers with the same base (in this case the base is 6), the result is the base raised to the power of the two exponents added together.

6^1/3+1/4 = 6^x/y
6^7/12 = 6^x/y
 
So the product would be 6^7/12
x = 7
y = 12</span>
6 0
2 years ago
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