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REY [17]
3 years ago
12

A regular hexagon has sides of 3 feet. What is the area of the hexagon?

Mathematics
1 answer:
Dominik [7]3 years ago
7 0

Answer:

13.5√(3) ft^2

Step-by-step explanation:

In this, question, we are to calculate the area of the hexagon

Mathematically, we can calculate the area of a hexagon using the formula;

A = {3√(3)/2}a^2

where a is the length of the side which is 3 feet

substituting the value of 3 into the formula, we have;

A = 3√3/2 * 3^2 = 27 √(3)/2 = 13.5√(3) ft^2

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150 less than k is 39
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Answer:

your answer is 121

Step-by-step explanation:

7 0
3 years ago
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Can you please help me? Keep it a little basic. (no decimals) Thanks for the help!
Delvig [45]
When you are dividing fractions you just flip the second fraction upside down and multiply the two fractions
So the first is
½ x 6/1 = 6/2 = 3

For the second you write them as improper fractions then do the same
So it is
3/2 / 1/8 = 3/2 x 8/1 = 24/2 = 12

So the answer to the first question is 3 and the second is 12
4 0
3 years ago
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The average value of two positive numbers is 30% less than one of the two numbers. By which percentage is average value bigger t
Viefleur [7K]

Answer:

75% bigger

Step-by-step explanation:

Let the first number be x and the second be y.

So:

Average = \frac{x + y}{2}

And:

Average = (1 - 30\%) * x -----30% less than x

Substitute Average = (1 - 30\%) * x in Average = \frac{x + y}{2}

\frac{x + y}{2} = (1 - 30\%) * x

\frac{x + y}{2} = (1 - 0.30) * x

\frac{x + y}{2} = 0.70 * x

\frac{x + y}{2} = 0.70x

Cross multiply

x + y = 0.70x * 2

x + y = 1.40x

Collect like terms

1.40x - x = y

0.40x = y

Make x the subject

x = \frac{y}{0.40}

x = 2.50y

So, the average is:

Average = (1 - 30\%) * x

Average = (1 - 30\%) * 2.50y

Average =0.70 * 2.50y

Average =1.75y

Rewrite as:

Average =(1 + 0.75)y

Express as percentage

Average =(1 + 75\%)y

This means that the average is 75% bigger than the second number

6 0
2 years ago
A sailor is 30m above the water in the crow's nest on a sailboat. The sailor encounters an orca surface at an angle of depressio
Natali [406]

Given :

A sailor is 30 m above the water in the crow's nest on a sailboat.

The sailor encounters an orca surface at an angle of depression of 15 degrees.

The crows nest is 20 m horizontally from the bow (front) of the boat.

To Find :

How far in front of the boat is the orca.

Solution :

Let, distance of boat front from the crow's nest is x.

So,

\dfrac{30}{20+x}=tan \ 15^{\circ}\\\\x=\dfrac{30}{tan \ 15^{\circ}}-20\\\\x=111.94-20\\\\x=91.94\ m

Hence, this is the required solution.

4 0
3 years ago
2.
Lynna [10]

In 15 minutes, Jada would have covered about 2.5 miles, while the cousin would have covered 0.625 miles.

<h3>What is speed?</h3>

Speed is the ratio of distance to time.

For Jada:

Speed = 2 miles / 12 minutes = 0.167 miles per minute

For Jada cousin:

Speed = 1 mile / 24 min = 0.0417 miles per minute.

Hence, in 15 minutes:

Jada distance = 15 min * 0.167 miles per minute = 2.5 miles

Jada cousin distance = 15 min * 0.167 miles per minute = 0.625 miles

In 15 minutes, Jada would have covered about 2.5 miles, while the cousin would have covered 0.625 miles.

Find out more on speed at: brainly.com/question/4931057

6 0
2 years ago
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