Answer:
Refer picture enclosed
Step-by-step explanation:
Given is a line BA and a point P. We have to construct a line perpendicular to BA through P.
Case I: P lies on the line BA
Without loss of generality assume BP is smaller than AP.
Cut an arc C on AB from P such that BP=CP
Now with B and C as centres draw arc up and down the line with more than half length of BC
Join the intersecting of arcs. That line is the perpendicular for BA through P.
This is because of concurrency of two triangles above the line BC
Case2:
P lies outside the line. Measure PB and cut an arc of BA with length PB
Let the point be C
Then CP=BP
NOw do as we did before the line with arcs more than 1/2 length of BC from B and C only down. Join the point of intersection down with P. This line will be perpendicular through P to BA
Answer:
The answer is 1 1/2 = 3/2 1 = 2/2 LCD=2
It will be 48/52 because there are 4 kings so 52-4=48
Answer:
The width of lot B is 11 feet, so option A is correct.
Step-by-step explanation:
Given:
- Two rectangular properties share a common side.
- Lot A is 33 feet wide and 42 feet long.
- The combined area of the lots = 1,848 square feet.
To find:
How many feet wide is Lot B?
Solution:
we know that, area of a rectangle is length x breadth
Then area of lot A = 33 x 42 = 1386 square feet.
And area of lot B = width x 42
Now, we are given that, total area = 1848
area of lot A + area of lot B = 1848
1386 + width x 42 = 1848
width x 42 = 1848 – 1386
width x 42 = 462
![width =\frac{42}{462}](https://tex.z-dn.net/?f=width%20%3D%5Cfrac%7B42%7D%7B462%7D)
width = 11
Hence, the width of lot B is 11 feet, so option A is correct.