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Nezavi [6.7K]
3 years ago
14

Can someone please help me with this problem. I will give brainliest!

Mathematics
1 answer:
Kobotan [32]3 years ago
5 0
<h3>Answer:   y = 5</h3>

Explanation:

The y axis is vertical. Anything perpendicular to this is horizontal.

All horizontal linear equations are of the form y = k, where k is any number.

In this case, k = 5 so that the line y = 5 goes through all points with y coordinate 5. Two points on this line are (-4,5) and (1,5).

Note how y = 5 is equivalent to y = 0x+5. We see the slope is 0 and the y intercept is 5. Compare this to y = mx+b.

You might be interested in
5/6v+10=5 what is the answer
yulyashka [42]

Answer:

x= -3/2

Step-by-step explanation:

You would multiply both sides by 6x+10 and then that would give you 5-5)6x+10) and you would divide both sides by 5. This would give you 1=6x+10, you would then try to isolate the 6x giving you -6x=10-1  or -6x=9 and you would see if the solutions are in the defined ranges so x=-5/3 is NOT in the defined range but x=-3/2 is.

6 0
3 years ago
PLEEEEEEEEEEEEEEEEEEEEEEEEEAAAAAAAAAAAAAASEEEEEEEEEEE ANYONE HELP.DO A FAVOUR AND ANSWER THIS QUESTION. IT IS A SIMPLE QUESTION
adell [148]
Here's how to figure out this problem: add up all the numbers in the mark category and divide by the # of numbers there are.

So....

6 + 7 + 8 + 9 + 10 ÷ 5 = 8

8 is your final answer.
4 0
3 years ago
If the second term of a geometric sequence of real numbers is -2 and the fifth term is 16 then what is the fourteenth term?
Agata [3.3K]
<h3>Given</h3>

A geometric sequence such that ...

a_2=-2\quad\text{and}\quad a_5=16

<h3>Find</h3>

a_{14}

<h3>Solution</h3>

We can use the ratio of the given terms to find the common ratio of the sequence, then use that to find the desired term from one of the given terms. We don't actually need the common ratio (-2). All we need is its cube (-8).

a_2=a_1r^{(2-1)}=a_1r^1\\a_5=a_1r^{(5-1)}=a_1r^4\\a_{14}=a_1r^{(14-1)}=a_1r^13=a_5r^9\\\\\dfrac{a_5}{a_2}=\dfrac{a_1r^4}{a_1r^1}=r^3=\dfrac{16}{-2}=-8\\\\r^9=\left(r^3\right)^3=(-8)^3=-512\\a_{14}=a_5(-512)\\\\a_{14}=-8192

7 0
3 years ago
For what value of x is sin x = cos 19°, where 0°&lt; x &lt; 90°? 38°
Digiron [165]
Sin x =cos 19 X =sin^1(cos 19) X=71
6 0
3 years ago
Read 2 more answers
!Help Help Help! lols
Gwar [14]

the Answer is c. I think

6 0
3 years ago
Read 2 more answers
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