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fredd [130]
3 years ago
9

For what value of x is sin x = cos 19°, where 0°< x < 90°? 38°

Mathematics
2 answers:
Digiron [165]3 years ago
6 0
Sin x =cos 19 X =sin^1(cos 19) X=71
Olin [163]3 years ago
6 0

Answer:

x = 71.

Step-by-step explanation:

Given  : sin x = cos 19°, where 0°< x < 90°.

To find : For what value of x .

Solution : We have given

sin x = cos 19°.

By the trigonometric rule sin x = cos ( 90 -x ).

We can write cos ( 90 -x ) in place of sin x.

cos ( 90 -x ) = cos 19°.

Then

90 - x = 19 .

On subtracting both sides by 90

-x = 19 -90 .

- x = -71.

On dividing by -1

x = 71.

Therefore, x = 71.

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Step-by-step explanation:

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8 0
3 years ago
Julie cashed a paycheck and repaired her brother $10 that she borrowed from him. She then spent $30 on fuel for her car and half
pochemuha
Remark
She starts out with x
She spends 10 dollars paying back her brother (that's - 10)
She spends 30 dollars on fuel (that - 30)
She spends 1/2 what's left on a tent ( that's 1/2 (x - 10 - 30) )
She then spent 29.45  on running shoes. 1/2 (x - 10 - 30) + 29.45 is her expenditures.

After all that she has 17.75 left. 

Equation
x - 10 - 30 - 1/2(x - 10 - 30) - 29.45 = 17.75   

Solve
Begin by adding 29.95 to both sides. 
x - 10 - 30 - 1/2(x - 10 - 30)  = 17.75 + 29.45 
x -10 - 30 - 1/2(x - 10 - 30)  = 47.20  Add the like terms on the left.
x - 40 - 1/2(x - 40) = 47.20 Add 40 to both sides. Don't go inside the brackets.
x - 1/2x + 1/2 (40) = 87.20
1/2 x + 20 = 87.20                        Subtract 20 from both sides.
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x = 134.40 


3 0
3 years ago
Read 2 more answers
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