Answer:
At the same rate 18 carburetors out of 1,050 could be expected to be detective.
Step-by-step explanation:
The number of carburetors tested = 175
Defective pieces out o f 175 = 3
So, ratio of defected to tested = 3 : 175
Now, the number of carburetors tested in second batch = 1,050
Here, let the defective pieces = m
So, by the Ratio of Proportion,
or, 
⇒ m = 18
Hence, at the same rate 18 carburetors out of 1,050 could be expected to be detective.
9514 1404 393
Answer:
x = y = 12
Step-by-step explanation:
A right triangle with a 45° angle is an isosceles right triangle. That means the legs are both the same length. The side ratios of such a triangle are ...
1 : 1 : √2
Multiplying these ratios by 12 gives ...
12 : 12 : 12√2 = x : y : 12√2
The side lengths x and y are both 12 units.
Answer:
its is x=0
Step-by-step explanation:
Answer:
43.75 ft²
Step-by-step explanation:
= (l√(w/2)² + h²) + (w√(l/2)² + h²)
l & w become 3.5, and h becomes 6.
<em /><em> </em>= (3.5√(3.5/2)² + 6²) + (3.5√(3.5/2)² + 6²)
<em>Step 1:Because this is a square pyramid, what you see above essentially becomes what you see below.</em>
<em /> = 2(3.5√(3.5/2)² + 6²)
<em>Step 2: Divide 3.5 by 2 to get 1.75.</em>
<em /><em> </em>= 2(3.5√1.75² + 6²)
<em>Step 3: Square both 1.75 and 6 to get 3.0625 and 36 respectively.</em>
= 2(3.5√3.0625 + 36)
<em>Step 4: Add 3.0625 and 36 to get 39.0625.</em>
<em /> = 2(3.5√39.0625)
<em>Step 5: The square root of 39.0625 is 6.25.</em>
<em /><em> </em>= 2(3.5 * 6.25)
<em>Step 6: Multiply 3.5 by 6.25 to get 21.875.</em>
<em /> = 2(21.875)
<em>Step 7: Multiply 2 by 21.875 to get 43.75.</em>
<em /> = 43.75 ft²
The lateral area of this pyramid is 43.75 ft².
<em />
<em />
Answer:
<h2>3(cos 336 + i sin 336)</h2>
Step-by-step explanation:
Fifth root of 243 = 3,
Suppose r( cos Ф + i sinФ) is the fifth root of 243(cos 240 + i sin 240),
then r^5( cos Ф + i sin Ф )^5 = 243(cos 240 + i sin 240).
Equating equal parts and using de Moivre's theorem:
r^5 =243 and cos 5Ф + i sin 5Ф = cos 240 + i sin 240
r = 3 and 5Ф = 240 +360p so Ф = 48 + 72p
So Ф = 48, 120, 192, 264, 336 for 48 ≤ Ф < 360
So there are 5 distinct solutions given by:
3(cos 48 + i sin 48),
3(cos 120 + i sin 120),
3(cos 192 + i sin 192),
3(cos 264 + i sin 264),
3(cos 336 + i sin 336)
