Question

What solutions to the following quadratic 3x^2 +15x-18=0

Answer 1

Answer:

x=-6 and x=1

Step-by-step explanation:

Given that:

$3x^2+15x-18$

Now,

$3x^2+15x-18=0$

Using the quadratic formula where a=3, b=15, and C=-18

x=-b±$\sqrt{b^2-4ac} /2a$

x=-15±${\sqrt{15^2-4(3)(-18} } /2(3)$

x=-15±$\sqrt{441} /6$

the discriminant $b^2-4ac>0$

So, there are two real roots

x=-15±21/6

$x=\frac{6}{6} \\x=1\\x=\frac{-36}{6} \\x=-6$

Therefore, x=-6 and x=1

Answer 2

The solutions would be x1=-6 and x2= 1