Answer:
E
Step-by-step explanation:
U = - 4 i + 1 j
v = 4 i + 1 j
| u | = √ (-4)² + 1² = √ 17
| v | = √4² + 1² = √ 17
| u + v | = √(u + v)²=
= √( u² + 2 u v + v² )= ...
cos ( u, v ) = (-16+1) / (|u| |v|) = -15/17
...= √(17 + 2 · √17 · √17 · ( -15/17) +17) =
= √ 34 - 30 = √ 4 = 2
Answer: C ) 2
Answer:
0.9
Step-by-step explanation:
10% is equal to 0.1
The probability of having defective parts in a pile of parts is 0.1
Before the process is stopped, 1 part has to be defective.
In a pile of 9 parts, the probability that a part is defective 0.1 of 9, which is = 0.9 hence, approximately one (1) part will be defective in a pile of 9 parts and the process will be stopped.
Since there was no defective part among the first 6 parts, P(d) was 0
That is, probability of a defective part was zero.
Dy/dx = -y inx iny
(y in x in y) dx + dy = 0
(y in x in y ) dx = - dy
(in x )dx = - (1/ y in y) dy
you just need to integrate both sides
Hope this helps
Answer:
6 and 7
Step-by-step explanation:
now make me brainliest
