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Advocard [28]
3 years ago
7

Here's a better picture sorry for the lad on but please help.

Mathematics
1 answer:
Natalija [7]3 years ago
7 0

Answer:

it would be r/8 = 4 , and the other answer 32

Step-by-step explanation:

because the teacher divides the ropes among 8 students so r/8 because you don't know the amount of ropes therefore it would be a variable

you multiply 8×4=32 so 32/8= 4

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ANSWER:-

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Find the measure of arc DB in P<br><br>please hurry if you can​
jeyben [28]

\quad \huge \quad \quad \boxed{ \tt \:Answer }

\qquad \tt \rightarrow \:m\overbrace{DB}= 90 \degree

____________________________________

\large \tt Solution  \: :

\qquad \tt \rightarrow \: m \overbrace{DB}  + m \overbrace{TB}  = 180 \degree

[ linear pair ]

\qquad \tt \rightarrow \: m \overbrace{DB}  + 90 \degree  = 180 \degree

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\qquad \tt \rightarrow \: m \overbrace{DB}    =   90 \degree

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8 0
2 years ago
59:19
Vesna [10]

nA.Replace ''the difference with subtraction

B.Replace''the number of serving '' with a variable x.

C.Replace ''four'' with 4.

Step-by-step explanation: .

8 0
1 year ago
I need help bruv. For the function y=x^2 - 5x - 6 .
lara [203]

Answer:

a. Vertex = (2.5,-12.25)

b. y-intercept = (0,-6)

c. x-intercept = (6,0) ; (-1,0)

Step-by-step explanation:

a.

Your equation is written as:

y = ax^{2} + bx +c

The easiest way to find the vertex is writing the equation this way:

y = a(x-h)^{2}+k

Being the vertex (h,k)

So first complete the square

y = x^{2} -5x -6 \\y = x^{2} - 2(2.5x) -6 \\y = x^{2} - 2(2.5x) +2.5^{2} - 2.5^{2} -6 \\y = (x^{2} -2(2.5x) + 2.5^{2}) -6.25 - 6 \\y = (x-2.5)^{2} -12.25

Vertex : (2.5,-12.25)

b.

To find the y-intercept you need to replace the equation when x = 0 and get y

y = (0)^{2} - 5(0) -6\\y = - 6

c.

To find the x-intercept you need to replace the equation when y = 0 and get x

0 = x^{2} - 5x -6 \\0 = (x-6)(x+1)\\x = 6\\x = -1

4 0
3 years ago
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