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3 years ago

Isolate c in the equation a=b(1/c-1/d)

Mathematics

1 answer:

Irina-Kira [14]3 years ago

5 0

A=b/c -b/d
a+b/d=b/c
(da+b)/d=b/c
db=(da+b)c
c=db/da+b

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Goods sold to Raman for rs 16000 & received partiat payment of 6000

lawyer [7]

Step-by-step explanation:

1.RamanA/c dr.6000

to sale a/c 16000

2.cash a/c.6000

to remain 6000

4 0

2 years ago

Meline has 4 different coloured crayons and 2 different boxes. How many different ways can Meline put all 4 different crayons in

BlackZzzverrR [31]

Answer:

<h2>3 different ways</h2>

Step-by-step explanation:

If Melinda has 4 different crayon and 2 different boxes and she is to put all 4 crayons into the two boxes so that each box has at least 1 crayon, this can be achieved as follows. Note that at least one crayon must be in each box, this means no box must be left empty. Each box can take any number of crayon from 1 and above.

First box Second box

1 crayon 3 crayons (first way)

2 crayons 2 crayons (2nd way)

3 crayons 1 crayon (3rd way)

This means that crayons can be divided into each box in <u>3 different ways</u> provided that each box has at least 1 crayon.

8 0

2 years ago

Tor given terms. Find how much the account needs to hold to make this possible. Round your answer to the nearest dollar. Regular

Novosadov [1.4K]

Answer:

https://www.omnicalculator.com/finance/compound-interest

Step-by-step explanation:

this is a link to a compound interest calculator and it helped me with similar problems hope it helps you

5 0

2 years ago

Part 1: What mistake did AJ make in the graph?

grigory [225]

Answer:

Part 1) AJ drawn the parabola opening upwards, instead of drawing it opening downwards

Part 2) see the explanation

Step-by-step explanation:

Part 1) What mistake did AJ make in the graph?

we have

$f(x)=-(x+2)^2-1$

This is the equation of a vertical parabola written in vertex form

The parabola open downward (because the leading coefficient is negative)

The vertex represent a maximum

The vertex is the point (-2,-1)

therefore

AJ drawn the parabola opening upwards, instead of drawing it opening downwards

Part 2) Evaluate any two x-values (between -5 and 5) into AJ's function. Show your work. How does your work prove that AJ made a mistake in the graph?

take the values x=-4 and x=4

For x=-4

substitute the value of x in the quadratic equation

$f(x)=-(-4+2)^2-1\\f(x)=-5$

For x=4

substitute the value of x in the quadratic equation

$f(x)=-(4+2)^2-1\\f(x)=-37$

According to AJ's graph for the value of x=-4 the function should be positive, however it is negative and for the value of x=4 the function should be positive and the function is negative

therefore

AJ made a mistake in the graph

8 0

2 years ago

This is geometry pls help will mark brainliest!!

adoni [48]

The Correct Answer Should Be - 70

I Hope This Helps You!!! :)

8 0

2 years ago

Read 2 more answers