Question

I'm supposed to write out an algebraic equation, and then solve the equation. If you can help me, with work shown, you'll get voted Brainliest.
Find three consecutive even integers such that four times
the first minus the third is six more than twice the second.​

Answer 1

Answer:

simple just follow me and mark it brainliest

Step-by-step explanation:

LET THE THREE CONSECUTIVE EVEN INTEGERS BE

(x+2) ,(x+4) ,(x+6)

then

according to the question

4(x+2) – (x+6) = 2(x+4) + 6

4x + 8 – x – 6= 2x + 8+6

3x +2 = 2x + 14

3x – 2x= 14 –2

x= 12

the numbers are

14

16

18

Answer 2

Answer:

The three numbers are 14, 16, 18.

Step-by-step explanation:

Consecutive even integers differ by 2.

You can let the smallest of the three numbers equal x. Then the other two numbers are x + 2 and x + 4.

Now use x, x + 2,and x + 4 to represent the 3 numbers and follow the directions to write an equation. The equation will have only one variable, x, so you can solve for x.

"four times the first" ----->   4x

"minus the third"   ------->    -(x + 4)

"is"  ----->     =

"six more than twice the second"   ------>    2(x + 2) + 6

Put all the pieces in boldface together to arrive at your equation.

4x - (x + 4) = 2(x + 2) + 6

Simplify the parentheses on both sides by distributing.

4x - x - 4 = 2x + 4 + 6

Combine like terms on both sides.

3x - 4 = 2x + 10

Subtract 2x from both sides.

x - 4 = 10

Add 4 to both sides.

x = 14

The smallest number is 14.

x + 2 = 14 + 2 = 16

x + 4 = 14 + 4 = 18

Answer: The three numbers are 14, 16, 18.