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katovenus [111]
3 years ago
7

I'm supposed to write out an algebraic equation, and then solve the equation. If you can help me, with work shown, you'll get vo

ted Brainliest.
Find three consecutive even integers such that four times
the first minus the third is six more than twice the second.​
Mathematics
2 answers:
Arada [10]3 years ago
5 0

Answer:

simple just follow me and mark it brainliest

Step-by-step explanation:

LET THE THREE CONSECUTIVE EVEN INTEGERS BE

(x+2) ,(x+4) ,(x+6)

then

according to the question

4(x+2) – (x+6) = 2(x+4) + 6

4x + 8 – x – 6= 2x + 8+6

3x +2 = 2x + 14

3x – 2x= 14 –2

x= 12

the numbers are

14

16

18

jarptica [38.1K]3 years ago
4 0

Answer:

The three numbers are 14, 16, 18.

Step-by-step explanation:

Consecutive even integers differ by 2.

You can let the smallest of the three numbers equal x. Then the other two numbers are x + 2 and x + 4.

Now use x, x + 2,and x + 4 to represent the 3 numbers and follow the directions to write an equation. The equation will have only one variable, x, so you can solve for x.

"four times the first" ----->   4x

"minus the third"   ------->    -(x + 4)

"is"  ----->     =

"six more than twice the second"   ------>    2(x + 2) + 6

Put all the pieces in boldface together to arrive at your equation.

4x - (x + 4) = 2(x + 2) + 6

Simplify the parentheses on both sides by distributing.

4x - x - 4 = 2x + 4 + 6

Combine like terms on both sides.

3x - 4 = 2x + 10

Subtract 2x from both sides.

x - 4 = 10

Add 4 to both sides.

x = 14

The smallest number is 14.

x + 2 = 14 + 2 = 16

x + 4 = 14 + 4 = 18

Answer: The three numbers are 14, 16, 18.

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Captain Ben has a ship, the H.M.S Crimson Lynx. The ship is five furlongs from the dread pirate Luis and his merciless band of t
grigory [225]

Answer:

We can see that this is dependent probability. We can find dependent probability of happening event A then event B by multiplying probability of event A by probability of event B given that event A already happened.

Step-by-step explanation:

In our case event A is pirate hitting captain's ship and event B is captain missing pirate's ship. We have been given that pirate shoots first so pirate's ship can't be hit before pirate shoots his cannons. So probability of hitting captain's ship is 1/3. We have been given that if Captain Ben's ship is already hit then Captain Ben will always miss. So the probability of Captain missing the dread pirate's ship given the pirate Luis hitting the Captain ship is 1. Now to find probability that pirate hits Captain, but Captain misses we will multiply our both probabilities.

8 0
3 years ago
The first triangle is dilated to form the second triangle. Select True or False for each statement.
malfutka [58]

Answer:

these are the step to follow so A=bh

Step-by-step explanation: A=1/2bh A=bh A=1/2 (b=b)h this is an example so you can follow how i did this

3 0
2 years ago
Describe how to find the least common multiple of three numbers
notka56 [123]
Find all the prime factors of the three numbers. pick up the common factors, ONCE, then pick up the non-common factors one by one, multiply the factors, the product is the least common factor.
example: the least common multiple of 6, 8, and 15
6=2*3
8=2*2*2
15=3*5
Note: do not write 8 into 4*2, because 4 is not a prime number. you have to break the number down to prime factors only. 
Notice that 6 and 8 have a common factor 2, so pick up the 2;
 6 and 15 have a common factor of 3, so pick up the 3.
those are the only two shared factors, so 2×3
now pick up whatever is not shared:
the two 2s for 8 and the 5 for 15 is not shared, add 2, 2, and 5 to the multiplication: 2×3×2×2×5=120
120 is the least common multiples of 6,8, and 15

this is basically how it is done. I believe you can explain better in your own words. 

3 0
3 years ago
For question 22 please pick 1,2,3 or 4
RSB [31]
It’s gonna be number three :))
3 0
3 years ago
Write the equation of the function g(x) if g(x) = f(x - 3) +1 and f(x) = x3 + 1.
stealth61 [152]

Answer:

Solution,

f(x) = x^{3} + 1

Put x = x - 3,

f(x - 3) =  (x-3)^{3} + 1

Now,

g(x) = f(x - 3) + 1

or, g(x) =[ (x-3)^{3} +1 ] + 1

or, g(x) = x^{3} -9x^{2} + 27x - 1 + 1+1

or, g(x) = x^{3} - 9x^{2} +27x + 1

6 0
2 years ago
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