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4 years ago

How do you change the answers into the correct number of digit?

Mathematics

1 answer:

Jobisdone [24]4 years ago

7 0

What is the question here that I should answer?

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In parts (a) through (e) below, mark the given statement as True or False. Justify each answer. All vectors are in set of rea

Oxana [17]

Answer:

(c)

"The given statement is true, by definition of length of a vector $v$ , $||v|| = \sqrt{v\bullet v}$ "

Step-by-step explanation:

(a) $v \bullet v = || v ||^2$

That is completely correct Remember that if $v = (x_1,x_2,x_3)\\$ then

$v \bullet v = x_1*x_1+x_2*x_2+x_3*x_3 = x_1^2+x_2^2+x_3^2 = ||v||^2$

Therefore the correct answer would be (c).

"The given statement is true, by definition of length of a vector $v$ , $||v|| = \sqrt{v\bullet v}$ "

5 0

3 years ago

It is 18°C at 8 am, and 14°C by noon. The change in temperature from 8 am to noon is

Mashcka [7]

The answer to the question is B.

6 0

3 years ago

Find the perimeter of the quadrilateral.

levacccp [35]

<em><u>Question:</u></em>

Find the perimeter of the quadrilateral. if x = 2 the perimeter is ___ inched.

The complete figure of this question is attached below

<em><u>Answer:</u></em>

<h3>The perimeter of the quadrilateral is 129 inches</h3>

<em><u>Solution:</u></em>

The complete figure of this question is attached below

Given that, a quadrilateral with,

Side lengths are:

$4x^2 + 8x\ inches \\\\3x^2-5x+20\ inches \\\\7x + 30\ inches \\\\31\ inches$

The values of the side lengths when x = 2 are

$(4x^2+8x)=(4\times 2^2+8\times 2)=(4\times 4+16)=16+16=32\ inch\\\\(3x^2-5x+20)=(3\times 2^2-5\times 2+20)=(3\times 4-10+20)=12+10=22\ inch\\\\(7x+30)=(7\times 2+30)=14+30=44\ inch$

Perimeter of a quadrilateral = Sum of its sides

Perimeter of given quadrilateral = 32 + 22 + 44 + 31 = 129 inches

Thus perimeter of the quadrilateral is 129 inches

5 0

3 years ago

What is the range of this function?

Rzqust [24]

Greetings.

The range is the set of y-value.

The range starts from the minimum point to maximum point.

Our minimum point starts at 0 and maximum point starts less than infinity.

Therefore the range is 0<=y<+inf

However, we do not often write that, although it is right.

Therefore we write as y≥0

Thus, the answer is B choice.

5 0

3 years ago

4. Stella says the equation x^2−8x+y^2+2y=5 has a center of (4,−1) and a radius of 5. Is she correct? Why or why not?

Ostrovityanka [42]

<h2>Stella is correct about center and wrong about radius </h2>

Step-by-step explanation:

Equation of circle with (h,k) as center and radius r is given by,

(x-h)²+(y-k)² = r²

Here equation is

x²−8x+y²+2y=5

Changing in to (x-h)²+(y-k)² = r² form

x²−8x + 16 - 16 +y²+2y+1 - 1=5

(x-4)² - 16 + (y+1)² -1 = 5

(x-4)² + (y+1)² = 22

(x-4)² + (y+1)² = 4.69²

Center is (4,-1) and radius is 4.69

Stella is correct about center and wrong about radius

8 0

3 years ago