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SpyIntel [72]
3 years ago
5

How is  eukaryotic RNA processed before leaving the nucleus 

Biology
1 answer:
Paha777 [63]3 years ago
6 0

Answer:

Messenger RNA, or mRNA, leaves the nucleus through pores in the nuclear membrane. ... During mRNA processing, the introns (non-coding regions) of the pre-mRNA are removed, and the exons (the coding regions) are spliced together. Additionally, a 5' cap and a 3' poly A tail are added to the pre-mRNA

Explanation:

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Protists are classified into what three groups
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<span>Protists are often classified by the characteristics that resemble those of fungi, plants, and animals</span>
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What word describes the majority of permanent genetic mutations?
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You experimentally change the DNA sequence directly upstream of a start codon of an operon in E coli to investigate the function
Phoenix [80]

Answer:

Mutation occurred in ribosome binding site that serves as binding site for 30S ribosomal subunit of <em>E. coli</em> and allows the process of protein synthesis to begin.

Explanation:

The initiation of protein synthesis in bacteria requires binding of the ribosome to the ribosome binding site. The ribosome binding site in bacteria consists of the initiation codon "AUG" and the preceding Shine-Dalgarno sequence. The AUG initiation codon and Shine Delgrano sequence are around 10 bases apart.

The sequence is polypurine hexamer and is represented by 5' ...AGGAGG...3'. Shine-Delgrano sequence is complementary to the conserved sequence present at the 3' end of 16SrRNA of the 30S subunit of the bacterial ribosome. Binding of Shine Delgrano sequence of ribosome binding site and the complementary sequence of the 30S ribosomal subunit marks the first step in the initiation of protein synthesis.

Any mutation in the ribosome binding site would not allow the process of protein synthesis to start or would reduce the rate of the initiation of protein synthesis.

8 0
3 years ago
Pleaaase help , and show work if you can
charle [14.2K]

Answer:

1. 39 J; 2. 3.9 % usable; 3. 96.1 % unusable

Step-by-step explanation:

1. Available energy

Energy consumed              = 1000 J

Less waste         = - 177 J

Less respiration = <u>-784 J </u>

Total energy lost                = <u>-961 J </u>

Available energy                =   39 J

2. Percent of total energy usable

The chipmunk could use only 39 J of the original 1000 J.

% of energy usable = 39 J/1000 J × 100 % = 3.9 %

3. Percent of energy unusable

The chipmunk lost 961 J of the original 1000 J.

% of energy unusable = 961 J/1000 J × 100 % = 96.1 %

6 0
3 years ago
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