<span>The most crucial principle of ELISA (enzyme-linked immunosorbent assay) is a highly specific antibody-antigen interaction.</span>
ELISA is a biochemical technique used to detect the presence of an antibody or an antigen in the biological sample. Simply described, in an ELISA, an antigen is immobilized on a solid surface and then a specific antibody is applied over the surface so that it can bind to the antigen. The antibody is usually linked to an enzyme, and in the final step, a substrate for that enzyme is added. The enzyme can convert it to some detectable signal, most commonly a color change. <span>Medical usage of ELISA is in the diagnosis of HIV infection, pregnancy tests, measurement of cytokines…</span>
Answer:
The correct answer is option d.
Explanation:
Based on the given question, the genotype of the male parent is aa, the genotype of the female parent is Aa, and the genotype of the offspring is AAa, showing trisomy characteristics. In the given case, the existence of two A chromosomes shows that the chromosomes non-disjunction at the time of gametogenesis have taken place in the female as she is the only one possessing A allele. Hence, it can be concluded that the disjunction is maternal in characteristic.
The duplication of chromosomes takes place at the time of the S-phase of meiosis. Thus, after going through S-phase, the karyotype of the cell will be AAaa (maternal gametogenesis), this set of the chromosome is termed as homologous pair, and the pair of AA or aa is termed as sister chromatids.
The meiotic disjunction takes place in two phases. First, in meiosis I disjunction, in this separation of homologous chromosomes takes place, that is, the maternal cell AAaa get differentiated into aa and AA daughter cells. Secondly, in meiosis II disjunction, the separation of sister chromatids takes place into two independent chromosomes, that is, the formation of two cells each comprising chromosome A from the AA cell and the formation of two cells each with chromosome a from the aa cell.
Thus, the phenomenon of non-disjunction would have taken place at the time of meiosis II in the case of a female gamete to exhibit two A chromosomes. Hence, the correct answer is option d.
Answer:
Increased exposure to X-rays
Explanation:
X-rays shoot harmful radiation through your body, that's why when you go to the dentist or other places and they take a X-ray they give you a lead vest to protect your organs from unneeded radiation.
hope this helps :)
The right answer is C
This process is called anaerobic respiration. It doesn't need dioxygen to occur (it can happen with or without O2).
Anaerobic respiration is a mechanism in which electrons pass through a chain of transporters whose final acceptor is a mineral substance other than oxygen, unlike aerobic respiration where the final acceptor is dioxygen. The final acceptor may be the nitrate ion (as in the case of Pseudomonas), carbon dioxyde or the sulfate ion.
Some bacteria (Pseudomonas) are able, anaerobically, to reduce nitrates to nitrites and then, depending on the case, to dinitrogen (with the enzyme Nitrate reductase A).
NO3- ==> NO2- ==> N2.
Answer:
The cells at the end of meiosis II must have half the number of chromosomes because, if they didn't have, the reunion of both gametes with diploid number of chromosomes for example, in gametes would form twice the number chromosomes.