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3 years ago

5

A tourism website claims travelers can see Europe for $75 a day. If a tourist saved $1,875 for a vacation, how many days can he

spend in Europe?

1 answer:

Contact [7]3 years ago

3 0

The answer is 25 days.
1875/75= 25

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A restaurant has 5 pizza toppings to choose from. How many different 2-topping pizzas are possible?

horsena [70]

10

Because if you do 5•2 you get 10

More in depth explanation:

Though there are 25 possible configurations the question asks for two different toppings together. It also asks for unique combinations. So AB and BA are the same combination in this context. The only unique possibilities are

AB
AC
AD
AE
BC
BD
BE
CD
CE
DE

It is easy to simplify this into 5•2 for this situation. And if the question asked for three toppings you would do 5•3.

However if the question asked for the configurations for two toppings then you would do 5•5 and if it asked for the configurations of 3 toppings you would do 5•5•5

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3 years ago

Given: SV || TU and SVX = UTX

Vladimir [108]

Answer: 2 is a given which is (SV | | TU)

I need help with the others.

Step-by-step explanation:

7 0

3 years ago

Lizzy is running a lemonade stand. She has a special price of $3 for 2 glasses of lemonade. She starts the day with no money. De

sveticcg [70]

Answer:

ercgtbvyuh7

Step-by-step explanation:

vhcrc6vthby7uj7vt6crgtvy

5 0

3 years ago

Please help!!! 20 points + brainliest!!<br> 6 + (-47) =

poizon [28]

Well, all we have to do is add, so:

6 + (-47) =

6 - 47 =

-41

5 0

3 years ago

Read 2 more answers

The earth rotates once per day about an axis passing through the north and south poles, an axis that is perpendicular to the pla

forsale [732]

Answer:

a)

Speed at Equator = 463.97 meters per second

Centripetal Acceleration at Equator = $3.37*10^{-2}$ meters per second squared

b)

Speed at 30 degrees north of equator = 401.79 meters per second

Centripetal Acceleration at 30 degrees north of equator = $2.92*10^{-2}$ meters per second squared

Step-by-step explanation:

The formula is:

$v=\frac{2 \pi R}{T}$

Where

v is speed

R is radius

T is time

and another formula for centripetal acceleration:

$a_c=\frac{4 \pi^{2} R}{T^2}$

Now,

a)

at equator, the radius is radius of earth (given), time in seconds is

T = 24 * 60 * 60 = 86,400

THus,

$v_E=\frac{2 \pi (6.38*10^{6}}{86,400}=463.97$

Speed at Equator = 463.97 meters per second

Centripetal Acceleration:

$a_{cE}=\frac{v_E^2}{R_E}=\frac{463.97}{6.38*10^{6}}=3.37*10^{-2}$

Centripetal Acceleration at Equator = $3.37*10^{-2}$ meters per second squared

b)

At 30.0° north of the equator:

$R_N=R_E Cos (30)= (6.38*10^6)Cos(30)=5.53*10^6$

Now,

Speed = $v_{30N}=\frac{2 \pi (5.53*10^6)}{86,400}=401.79$

Speed at 30 degrees north of equator = 401.79 meters per second

Centripetal Acceleration:

$a_{30N}=\frac{v_E^2}{R_E}=\frac{401.79}{5.53*10^6}=2.92*10^{-2}$

Centripetal Acceleration at 30 degrees north of equator = $2.92*10^{-2}$ meters per second squared

4 0

3 years ago