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miskamm [114]
3 years ago
5

The following data are from a completely randomized design.

Mathematics
1 answer:
taurus [48]3 years ago
5 0
Sorry I need the 2 answers to ask my own. I wouldn’t of understood this wnywyas. Hopefully you find someone who can do it
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The total cost (c) in dollars of renting a car for n days is given by the inequality LaTeX: c\ge125+50nc ≥ 125 + 50 n. What is t
zysi [14]

Answer:

<h3>6 days</h3>

Step-by-step explanation:

Given the inequality expression of the total cost (c) in dollars of renting a car for n days as c ≥ 125 + 50n

To get the maximum number of days for which a car could be rented if the total cost was $425, substitute c = 425 into the expression and find n

425 ≥ 125 + 50n

Subtract 125 from both sides

425 - 125 ≥ 125 + 50n  - 125

300≥ 50n

Divide both sides by 50

300/50≥50n/50

6 ≥n

Rearrange

n≤6

<em>Hence the maximum number of days for which a car could be rented if the total cost was $425 is 6days</em>

<em></em>

5 0
3 years ago
Describe a situation that could be modeled with the ratio 3: 1.
ehidna [41]

Answer:

three boys to 1 girl

Step-by-step explanation:

a

5 0
3 years ago
Read 2 more answers
Gavin drank nine 8 ounce glasses of water today. How many quarts of water did he drink
dsp73

Answer:

2.25

Step-by-step explanation:

7 0
3 years ago
A random sample of 121 automobiles traveling on an interstate showed an average speed of 73 mph. from past information, it is kn
tatiyna

121 is big enough to assume normality and not worry about the t distribution. By the 68-95-99.7 rule a 95% confidence interval includes plus or minus two standard deviations. So 95% of the cars will be in the mph range


(73 - 2 \cdot 11, 73 + 2 \cdot 11) = (51,95)


The question is a bit vague, but it seems we're being asked for the 95% confidence interval on the average of 121 cars. The 121 is a hint of course.


The standard deviation of the average is in general the standard deviation of the individual samples divided by the square root of n:


\sigma = \dfrac{ 11}{\sqrt{121}} = 1


So repeating our experiment of taking the average 121 cars over and over, we expect 95% of the averages to be in the mph range


(73 - 2 \cdot 1, 73 + 2 \cdot 1) = (71,75)


That's probably the answer they're looking for.



4 0
3 years ago
Find x plss:))))))))
Galina-37 [17]

Answer:

180 - 90 = 90

half of 90 = 45

40 and 50??

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
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