so, we know the dimensions of the pool, is a 20x10, so its area is simply 200 ft², and we know the walkway is 216 ft², so the whole thing, including pool and walkway is really 200 + 216 ft².

now, as you see in the picture, the dimensions for the combined area is 20+2x and 10+2x, since the walkway is "x" long, therefore,

$\bf \stackrel{length}{(20+2x)}\stackrel{width}{(10+2x)}=200+216\implies \stackrel{FOIL}{4x^2+60x+200}=200+216 \\\\\\ 4x^2+60x=216\implies \stackrel{dividing~by~4}{x^2+15x=54} \\\\\\ x^2+15x-54=0\implies (x+18)(x-3)=0\implies x= \begin{cases} -18\\ \boxed{3} \end{cases}$

notice, it cannot be -18, since is a positive length unit.

5 0

2 years ago

Read 2 more answers

Solve for X<br><br> Thank youuu

maksim [4K]

Answer:

x= -4

Step-by-step explanation:

∠LMP + ∠PMN= 180° (adj. ∠s on a str. line)

-16x +13 -20x +23= 180

bring x term to 1 side, constant to the other:

-36x= 180 -13 -23

Simplify:

-36x= 144

x= 144 ÷ (-36)

x= -4

*The sum of the angles on a straight line is 180°

6 0

2 years ago

Ms. Brown's class is learning about banks, so she creates one in her classroom. All students start with $75 in their accounts. L

Katen [24]

Answer:

can you show the students balance at the end of activity ??

Step-by-step explanation:

4 0

2 years ago