1) A(-5,-3); B(-6,-1); C(-3,-1) ; D(-2,-3)
When a refection is done about x-axis, the values of the abscise x remain identical & the value of ordinate just change their signs:
A(-5,-3); A'(-5,+3)
B(-6,-1); B'(-6,+1)
C(-3,-1); C'(-3,+1)
D(-2,-3); D'(-2,+3)
2) A'B'C'D' is translated 3 UNITS RIGHT, that means the ordinated of A'B'C'D'
are the same but the abscises have been increased by 3 UNITS ;
A'(-5,+3) ==>A"(-2,3)
B'(-6,+1) ==>B"(-3,1)
C'(-3,+1) ==>C"(0,1)
D'(-2,+3) ==>D"(1,3)
9/40.5=10/x
9x=405
X =45
When you set a proportion you can find the ? Value by cross multiplication
Answer:
The next three terms of the sequence are 17, 21 and 25.
The 300th term of the sequence is 1197.
Step-by-step explanation:
The statement describes an arithmetic progression, which is defined by following formula:
(1)
Where:
- First element of the sequence.
- Progression rate.
- Index of the n-th element of the sequence.
- n-th element of the series.
If we know that , and , then the progression rate is:
The set of elements of the series are described by .
Lastly, if we know that , then the 300th term of the sequence is:
And the next three terms of the sequence are:
n = 5
n = 6
n = 7
The next three terms of the sequence are 17, 21 and 25.
The 300th term of the sequence is 1197.
Answer:
60 miles
Step-by-step explanation:
Distance apart = 100
Rate of travel. :
Anthony = 12 mph
Cleopafda = 8 mph
Using the relation :
Speed = distance / time
Distance = speed * time
If they leave at the same time, travel time Can be represented as x
Anthony's distance + Cleopafda distance = total distance
12x +. 8x = 100
20x = 100
x = 5
Hence, they both traveled for 5 hours before meeting.
Distance covered by Anthony :
Speed * time
12 mph * 5h = 60 miles
Anthony must travel. For 60 miles.
Answer:
Step-by-step explanation:
We use positive exponent to display large numbers as smaller numbers. We use negative exponents to display extremely small decimals as easy to read numbers