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iren2701 [21]
3 years ago
14

Considera a sequencia: 5,9,13,17,21...Indica a expressão geradora desta sequencia. 5n 4n+1 5n-1 3n+1

Mathematics
1 answer:
Archy [21]3 years ago
7 0

Responder:

Tn = 4n + 1

Explicación paso a paso:

Dada la secuencia aritmética

5,9,13,17,21 ...

Debemos encontrar el enésimo término de la secuencia

Tn = una + (n-1) d

a es el primer término = 5

n es el número de términos

d es la diferencia común

d = 9-5 = 13-9

d = 4

Sustituir en la ecuación

Tn = 5+ (n-1) (4)

Tn = 5 + 4n-4

Tn = 4n + 5-4

Tn = 4n + 1

Por tanto, el enésimo término de la secuencia se expresa como Tn = 4n + 1

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