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3 years ago

Which number should.be added to the data so that the range of the data is 31? 54,72,64,57

Mathematics

1 answer:

Sergio039 [100]3 years ago

3 0

Answer: 41 or 85

<u>Step-by-step explanation:</u>

Range is the difference between the largest number and the smallest number.

The largest number is 72. 72 - 31 = 41

The smallest number is 54. 54 + 31 = 85

Adding either ONE of those numbers will result in a range of 31.

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Pls help, was sick the day I had to learn this

7nadin3 [17]

1. 13/3m
2. 24m to the 2nd power over 3 m
3.72 m to the 2nd power -11 over 3m
4.-16/3m

4 0

3 years ago

9+8{7•6-5[4+(3-2•1)]}=?

34kurt

Answer:

145

Step-by-step explanation:

Ⓗⓘ ⓣⓗⓔⓡⓔ

9+8{7*6-5[4+(3-2*1)}]}

9+8{7*6-5[4+1]}

9+8{7*6-25}

9+8{42-25}

9+136

145

(っ◔◡◔)っ ♥ Hope this helped! Have a great day! :) ♥

Please, please give brainliest, it would be greatly appreciated, I only a few more before I advance, thanks!

5 0

3 years ago

Tính đạo hàm <br>y=2x^3 - 9x^2 + 12x + 4

Liula [17]

Answer:

hihihihihihihihihihihihihihi

5 0

3 years ago

An instructor who taught two sections of engineering probability last term, the first with 20 students and thesecond with 30, de

Oliga [24]

Answer:

0.207

Step-by-step explanation:

This is an hypergeometric distribution problem

An hypergeometric distribution has the same sense as the discrete probabilities of binomial distribution, but unlike binomial distribution, hypergeometric distribution does not allow replacement.

Binomial distribution expresses the probability of picking k objects from n with replacement, but hypergeometric distribution expresses picking k objects from n without replacement, with the finite total population, N, containing K objects.

It is expressed mathematically as

h(k: n, K, N) = (ᴷCₖ)(ᴺ⁻ᴷCₙ₋ₖ)/(ᴺCₙ)

where

k = number of students in the 2nd section required to be in the first 15 graded projects (number of successes) = 10

n = total number of first graded projects (number of trials) = 15

K = number of students in the 2nd section of the class = 30

N = total number of students = 50

h(10: 15, 30, 50) = (³⁰C₁₀)(⁵⁰⁻³⁰C₁₅₋₁₀)/(⁵⁰C₁₅)

h(10: 15, 30, 50) = (³⁰C₁₀)(²⁰C₅)/(⁵⁰C₁₅)

= (30,045,015)(15,504)/(2,250,829,575,120)

P(X = 10) = 0.207

Hope this Helps!!!

7 0

3 years ago

Suppose the leader of a camping trip is putting together a trail mix

wel

Answer:

8 pounds of peanuts, 6 pounds of raisins and 6 pounds of chocolate chips

Step-by-step explanation:

Let x be the number of pounds of peanuts and y be the number of pounds of raisins and chocolate chips.

Peanuts cost $2 per pound, then x pounds cost $2x.

Raisins cost $2.50 per pound, then y pounds cost $2.50y.

Chocolate chips cost $4 per pound, then y pounds cost $4y.

In total, x+y+y=20 and those 20 pounds cost

2x+2.50y+4y=20·2.75.

Solve the system of two equations:

$\left \{ {{x+2y=20} \\ \\ \\ \\ \\ \\ \atop {2x+6.5y=55}} \right.$

From the first equation:

$x=20-2y$

Substitute x into the second equation:

$2(20-2y)+6.5y=55\\ \\40-4y+6.5y=55\\ \\2.5y=15\\ \\25y=150\\ \\y=6\\ \\x=20-2\cdot 6=8$

8 0

3 years ago