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3 years ago

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SAT

2 answers:

horsena [70]3 years ago

7 0

Answer:

blue

Explanation:

miv72 [106K]3 years ago

7 0

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The reading on the gauge were 2000 kpa what would the pressure in psi

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The answer is 290.0755

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3 years ago

9 x 20= Puntos libres

Gemiola [76]

Answer:

180

Explanation:

because you have to multiply 9 x 20 which gives you 180 for your total

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A box contains 40 number tiles numbered 1 to 40. If a tile is drawn at random, what is the probability that the number drawn is

BlackZzzverrR [31]

Explanation 1 P (3 or 4):

There are 40 number tiles numbered 1 to 40.

Multiple of 3 in 1 to 40 are:

There are 10 multiples till 30 (since $3 \times 10 = 30$ ) and then 33, 36, and 39 are other three multiples till 40. So there are 13 multiples of 3 from 1 to 40.

Multiples of 4 in 1 to 40 are:

There are 10 multiples till 40 (since $4 \times 10 = 40$ ) . So there are 10 multiples of 4 from 1 to 40.

Common Multiples of 3 and 4 in 1 to 40 is,

12, 28, 36, only 3

So, the probability of 3 or 4 is,

$P(\text {mult of 3})+P(\text {mult of 4}) -P(\text {mult of 3 and 4})$

$=\frac{13}{40} +\frac{10}{40} -\frac{3}{40}$

$=\frac{23}{40} -\frac{3}{40}$

$=\frac{20}{40}$

$=\frac{1}{2}$

So the probability of 3 or 4 is $\frac{1}{2}$ .

Explanation 2 P(4 or 5):

Multiples of 4 in 1 to 40 are:

There are 10 multiples till 40 (since $4 \times 10 = 40$ ) . So there are 10 multiples of 4 from 1 to 40.

Multiple of 5 in 1 to 40 are:

There are 8 multiples in 40 (since $5 \times 8 = 40$ ). So there are 8 multiples of 5 from 1 to 40.

Common Multiples of 4 and 5 in 1 to 40 is,

20 and 40 only 2

So, the probability of 4 or 5 is,

$P(\text {mult of 4})+P(\text {mult of 5}) -P(\text {mult of 4 and 5})$

$=\frac{10}{40} +\frac{8}{40} -\frac{2}{40}$

$=\frac{18}{40} -\frac{2}{40}$

$=\frac{16}{40}$

$=\frac{2}{5}$

So the probability of 4 or 5 is $\frac{2}{5}$ .

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4 years ago

Report your scores and conclusions from "When in doubt...guess." You should give 2 scores in fractional form and your conclusion

gladu [14]

Well you can find the answer on the first page

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4 years ago