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Inga [223]
3 years ago
15

What is the slope of the line that passes through point (-8,3) and (-8,2)?

Mathematics
1 answer:
PIT_PIT [208]3 years ago
6 0

Answer:

\frac{-1}{0} which is -1

Step-by-step explanation:

The slope formula is y2-y1 over x2-x1

So just plug it in. 2 - 3 = -1

-8 - -8 = 0

So the slope is -1 over 0

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What is the answer to this
mash [69]

Answer:

  • 250
  • decay
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Step-by-step explanation:

The value with the exponent is the "multiplier". It is 0.05.

This value is less than 1, so the function represents <em>decay</em>.

The initial value is the number that multiplies the exponential term. It is the value of A when t=0: 250.

  • original amount: 250
  • growth or decay: decay
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Point A is located at (4, −7). The point is reflected in the x-axis. Where is the image of A located?
DochEvi [55]

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Step-by-step explanation:

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3 years ago
Read 2 more answers
Given the equation square root of quantity 3x plus 6 end quantity equals 3, solve for x and identify if it is an extraneous solu
Novay_Z [31]

Solution is not extraneous, x=1 is correct answer

Step-by-step explanation:

We need to solve the equation \sqrt{3x+6}=3 and find value of x.

Solving:

\sqrt{3x+6}=3\\Taking\,\,square\,\,on\,\,both\,\,sides\\(\sqrt{3x+6})^2=(3)^2\\3x+6=9\\Simplifying:\\3x=9-6\\3x=3\\x=3/3\\x=1

So. Value of x = 1

Now checking if solution is extraneous or not

Solution is extraneous if value of x doesn't satisfy the given equation.

Checking: putting x=1 in the equation \sqrt{3x+6}=3

\sqrt{3x+6}=3\\\sqrt{3(1)+6}=3\\\sqrt{9}=3\\ 3=3

Since x=1, verifies the given equation so, x=1 is not extraneous solution

Solution is not extraneous, x=1 is correct answer

Keywords: Solving equations and finding extraneous roots

Learn more about Solving equations and finding extraneous roots at:

  • brainly.com/question/1626495
  • brainly.com/question/2959656
  • brainly.com/question/4046256

#learnwithBrainly

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3 years ago
Plz help fast!!?!!!!​
sineoko [7]

Answer:

so where's the question?

Step-by-step explanation:

4 0
3 years ago
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