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3 years ago

Work out the value of 23 - 4b. When b = 3

Mathematics

2 answers:

Serggg [28]3 years ago

8 0

Answer:

Step-by-step explanation:

Substitute 3 for b

23 - 4(3)

Multiply 4(3) = 12

23 - 12

Subtract

23 - 12 = 11

MA_775_DIABLO [31]3 years ago

7 0

Answer:

$11$

Step-by-step explanation:

$b = 3 \\ \\ 23 - 4b \\ 23 + 4 \times 3 \\ 23 - 12 \\ 11$

hope this helps you

Have a nice day!

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An individual head of a sprinkler system covers a circular area of grass with a radius of 25 feet. the yard has 3 sprinkler head

frutty [35]

Answer:

Option D. 5890.5 feet²

Step-by-step explanation:

An individual head of a sprinkler system covers a circular are of grass with a radius of 25 feet.

Yard has three sprinkler heads that each cover circular area with no overlap.

We have to calculate the approximate area watered by these 3 sprinkler heads.

Area covered by one sprinkler = π×r² = π×(25)² = 625π feet²

Therefore area covered by three sprinkler heads = 3 × 625π = 5892.85 feet²

which matches the approximate value of Option D. 5890.5 feet²

3 0

3 years ago

Read 2 more answers

What is a solution to the equation 3 / m + 3 - M / 3 - M equals m^2 + 9 / m^2-9?

Mnenie [13.5K]

Answer: Last option.

Step-by-step explanation:

Given the equation:

$\frac{3}{m+3}-\frac{m}{3-m}=\frac{m^2+9}{m^2-9}$

Follow these steps to solve it:

- Subtract the fractions on the left side of the equation:

$\frac{3(3-m)-m(m+3)}{(m+3)(3-m)}=\frac{m^2+9}{m^2-9}\\\\\frac{9-3m-m^2-3m}{(m+3)(3-m)}=\frac{m^2+9}{m^2-9}\\\\\frac{-m^2-6m+9}{(m+3)(3-m)}=\frac{m^2+9}{m^2-9}$

- Using the Difference of squares formula ( $a^2-b^2=(a+b)(a-b)$ ) we can simplify the denominator of the right side of the equation:

$\frac{-m^2-6m+9}{(m+3)(3-m)}=\frac{m^2+9}{(m+3)(m-3)}$

- Multiply both sides of the equation by $(m+3)(3-m)$ and simplify:

$\frac{(-m^2-6m+9)(m+3)(3-m)}{(m+3)(3-m)}=\frac{(m^2+9)(m+3)(3-m)}{(m+3)(m-3)}\\\\-m^2-6m+9=\frac{(m^2+9)(3-m)}{(m-3)}$

- Multiply both sides by $m-3$ :

$(-m^2-6m+9)(m-3)=\frac{(m^2+9)(3-m)(m-3)}{(m-3)}\\\\(-m^2-6m+9)(m-3)=(m^2+9)(3-m)$

- Apply Distributive property and simplify:

$(-m^2-6m+9)(m-3)=(m^2+9)(3-m)\\\\-m^3-6m^2+9m+3m^2+18m-27=3m^2+27-m^3-9m\\\\-m^3-3m^2+27m-27+m^3-3m^2+9m-27=0\\\\-6m^2+36m-54=0$

- Divide both sides of the equation by -6:

$\frac{-6m^2+36m-54}{-6}=\frac{0}{-6}\\\\m^2-6m+9=0$

- Factor the equation and solve for "m":

$(m-3)^2=0\\\\m=3$

In order to verify it, you must substitute $m=3$ into the equation and solve it:

$\frac{3}{3+3}-\frac{3}{3-3}=\frac{3^2+9}{3^2-9}\\\\\frac{3}{6}-\frac{3}{0}=\frac{18}{0}$

NO SOLUTION

7 0

3 years ago

What are the coordinates of the midpoint of the line segment with endpoints R(4,−7) and S(−3,5)?

tekilochka [14]

The answer is (.5,-1)

3 0

3 years ago

Find AC. B 7x-6 6x +4

almond37 [142]

answer:

put a picture of the question, it is easier to understand that way.

5 0

3 years ago

Simplify (x − 4)(2x2 + 3x − 5).

xeze [42]

The simplified form of given expression is $2x^3-5x^2-17x+20$

Solution:

Given that we have to simplify the expression

Given expression is:

$(x-4)(2x^2+3x-5)$

We can simplify the expression by multiplying each term in first bracket with each term term in second bracket

$\rightarrow (x-4)(2x^2+3x-5)$

$\rightarrow (x)(2x^2)+(x)(3x)+(x)(-5)-4(2x^2)-4(3x)-4(-5)$

Simplify the above expression by multiplying the numbers in each term and adding the coefficients of like variables in each term

$\rightarrow 2x^3+3x^2-5x-8x^2-12x+20$

Combine the like terms

$\rightarrow 2x^3+3x^2-8x^2-5x-12x+20$

$\rightarrow 2x^3-5x^2-17x+20$

Thus the expression is simplified

5 0

3 years ago