$\sin(2x + x) = \sin(2x) \cos(x) + \\ \cos(2x) \sin(x) = 2 \sin(x) { \cos(x) }^{2} \\ + \sin(x) { \cos(x) }^{2} - { \sin(x) }^{3} = \\ 3 \sin(x) { \cos(x) }^{2} - { \sin(x) }^{3} = \\ 3 \sin(x) - 3 { \sin(x) }^{3} - { \sin(x) }^{3} = \\ 3 \sin(x) - 4 { \sin(x) }^{3}$

3 0

3 years ago

Write the fraction as a mixed number. 9/2

atroni [7]

Do you need the number 9/2 simplified? if so, the answer is 4 1/2 :) hope this helps!

5 0

3 years ago

Help easy question!!

LenKa [72]

When you look at the x = 0 and y = -2, that is the y-intercept since the x = 0.

Then when you look at the second one, it goes right one and up four.

As rise over run, it would be 4 / 1 or simply 4.

The slope is 4 and the y-intercept is -2

Plug it in the equation: y = mx + b. M is the slope and B is the y-intercept.

y = 4x -2

5 0

3 years ago

Really need your help ​

Really need your help