Answer;
-Decrease
if the producer population decreased then the size of the herbivore population will consequently decrease.
Explanation;
Producers
are organisms that make make their own food through a process known as photosynthesis, e.g. plants such as grasses. Herbivores are the organisms which feed on producers. Examples of herbivores are rabbits, giraffes etc.
-An increase in producer population means that there will be a a corresponding increase in the population of herbivores while a decrease in the size of producers will cause a decrease in the population of herbivores.
Answer: The oxidation state of selenium in SeO3 is +6
Explanation:
SeO3 is the chemical formula for selenium trioxide.
- The oxidation state of SeO3 = 0 (since it is stable and with no charge)
- the oxidation number of oxygen (O) IN SeO3 is -2
- the oxidation state of selenium in SeO3 = Z (let unknown value be Z)
Hence, SeO3 = 0
Z + (-2 x 3) = 0
Z + (-6) = 0
Z - 6 = 0
Z = 0 + 6
Z = +6
Thus, the oxidation state of selenium in SeO3 is +6
<u>Answer:</u> The enthalpy of formation of HCN(g) is 135.1 kJ/mol
<u>Explanation:</u>
Enthalpy change is defined as the difference in enthalpies of all the product and the reactants each multiplied with their respective number of moles.
The equation used to calculate enthalpy change is of a reaction is:
For the given chemical reaction:
The equation for the enthalpy change of the above reaction is:
We are given:
Putting values in above equation, we get:
Hence, the enthalpy of formation of HCN(g) is 135.1 kJ/mol
Answer is: there is 1,368·10²⁵ atoms of carbon.
N(C₃H₈) = 4,56·10²⁴.
From molecular formula: in one molecule of propane there is three atoms of carbon:
N(C) = 3 · 4,56·10²⁴.
N(C) = 1,368·10²⁵.
The easiest way to do this is to assume that you have 100g of compound. Then you will have 69.9g of iron and 30.1g of oxygen.
You will need to find how many moles there are of each. Divide these masses by the molar mass of each element (for oxygen, just use the molar mass of O, not O2, as the calculation is easier with atoms than dioxygen):
69.9g / 55.845g/mol = 1.25mol Fe
30.1g / 15.999g/mol = 1.88mol O
Next, find the ratio of these 2 molar amounts. If we have 1 mole of Fe, we will have 1.88 / 1.25 = 1.50 mol O. Make everything whole numbers now: 1.50 is half of 3, so multiply both by 2. We get 2 moles of Fe to every 3 moles of O, so the empirical formula is Fe2O3.