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wel
3 years ago
14

What are the elements of a diatonic element??​

Chemistry
1 answer:
prisoha [69]3 years ago
4 0
Hydrogen, Nitrogen, Flourine, Oxygen, Iodine, Chlorine, Iodine, and Bromine.
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4Fe + 30₂ ⇒ Fe₂0₃
DaniilM [7]

Answer:

A

The nuber of each one should be same

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1 year ago
What is the correct formula
nataly862011 [7]

Answer:

A the answer is A I'm sure

7 0
3 years ago
Given the reactant side of the total ionic equation for the neutralization reaction of lithium hydroxide (LiOH) with hydrochlori
Sunny_sXe [5.5K]
<span>Answer:
</span><span>
</span><span>
</span><span>Li⁺ (aq) + OH⁻ (aq) + H⁺ (aq) + Cl⁻(aq) → Li⁺ (aq) + Cl⁻ (aq) + H₂O(l)</span><span />

<span>Explanation:
</span>

<span>1) Combine the cation Li⁺ (aq) with the anion Cl- (aq) to form LiCl(s).
</span>
<span>LiCl is a solid soluble substance, a typical ionic compound. So, it will reamain as separate ions in the product side: Li⁺ + CL⁻</span>

<span>2) Combine the anion OH⁻ with the cation H⁺ to form H₂O(l).
</span>
<span>Since, the ionization of H₂O is low, it will remain as liquid in the product side: H₂O(l)</span>

<span>3) Finally, you can wirte the total ionic equation:
</span>
Li⁺ (aq) + OH⁻ (aq) + H⁺ (aq) + Cl⁻(aq) → Li⁺ (aq) + Cl⁻ (aq) + H₂O(l)



8 0
2 years ago
Which has a larger radius Me or Xe?
IrinaVladis [17]
Xe is bigger:)

I hope I helped:)

Please leave a thanks:)
8 0
3 years ago
A flexible container at an initial volume of 4.11 L contains 2.51 mol of gas. More gas is then added to the container until it r
Nitella [24]

Answer:

7.81 moles

Explanation:

To solve this problem, let us generate an expression involving volume and number of mole of the gas since the pressure and temperature of the gas are constant.

From ideal gas equation:

PV = nRT

Divide both side by P

V= nRT/P

Divide both side by n

V/n = RT/P

Since RT/P are constant, then:

V1/n1 = V2/n2

Data obtained from the question include:

V1 = 4.11

n1 = 2.51 moles

V2 = 16.9L

n2 =?

Using the above equation i.e V1/n1 = V2/n2, the final number of the gas can be obtained as illustrated below:

4.11/2.51 = 16.9/n2

Cross multiply to express in linear form

4.11 x n2 = 2.51 x 16.9

Divide both side by 4.11

n2 = (2.51 x 16.9) / 4.11

n2 = 10.32moles

Now, to obtain the number of mole of the gas added, we'll subtract the initial mole from the final mole i.e

n2 — n1

Number of mole added = n2 — n1

10.32 — 2.51 = 7.81 moles

Therefore, 7.81 moles of the gas was added to the container

3 0
3 years ago
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