Answer:
33:100- 6:4- 5:3- 11/3
Step-by-step explanation:
First turn into even fractions
5:3= 1 2/3
6:4=1 1/2
11/3= 3 2/3
3/1= 3
33:100= 1/3
Then look at the numbers.
Answer:
f(10x-8)=-20x+22
f(g(x))
possibly
g(-2x+6)=-20x+52
g(f(x))
If needing a different answer math-way can possibly help you as it helped me.
Can you show the <span>graphs </span>
The main reason behind this is using properties of logarithm .
like
when solving
There you use multiplication property and make addition to multiplication then you get extraneous solution because in plenty of cases they occur
like
But
Same happens in case of logarithm
This problem can be readily solved if we are familiar with the point-slope form of straight lines:
y-y0=m(x-x0) ...................................(1)
where
m=slope of line
(x0,y0) is a point through which the line passes.
We know that the line passes through A(3,-6), B(1,2)
All options have a slope of -4, so that should not be a problem. In fact, if we check the slope=(yb-ya)/(xb-xa), we do find that the slope m=-4.
So we can check which line passes through which point:
a. y+6=-4(x-3)
Rearrange to the form of equation (1) above,
y-(-6)=-4(x-3) means that line passes through A(3,-6) => ok
b. y-1=-4(x-2) means line passes through (2,1), which is neither A nor B
****** this equation is not the line passing through A & B *****
c. y=-4x+6 subtract 2 from both sides (to make the y-coordinate 2)
y-2 = -4x+4, rearrange
y-2 = -4(x-1)
which means that it passes through B(1,2), so ok
d. y-2=-4(x-1)
this is the same as the previous equation, so it passes through B(1,2),
this equation is ok.
Answer: the equation y-1=-4(x-2) does NOT pass through both A and B.
