Answer:
The probability that a randomly chosen code starts with M and ends with E is 0.05 ....
Step-by-step explanation:
According to the given statement we have to make five letter code from A, F, E, R, and M without repeating any letter. We have to find that what is probability that a randomly chosen code starts with M and ends with E.
Thus the probability of picking the first letter M = 1/5
After that we require the sequence (not E, not E, not E) which is equal to:
= 3/4 * 2/3* *1/2
= 1/4
Now multiply 1/5 and 1/4
1/5 * 1/4
= 1/20
= 0.05
Therefore the probability that a randomly chosen code starts with M and ends with E is 0.05 ....
X + y = 9 Subtract x from both sides.
y = 9 - x
x^2 + y^2 = 53
x^2 + (9 - x)^2 = 53 Remove the brackets.
x^2 + 81 - 18x + x^2 = 53 Collect the like terms on the left.
2x^2 - 18x + 81 = 53 Subtract 53 from both sides.
2x^2 - 18x + 81 - 53 = 0
2x^2 - 18x + 28 = 0 This factors, but you can see it much easier if you pull out 2 as a common factor.
2(x^2 - 9x + 14) = 0
2(x - 2)(x - 7) =0 You could divide by 2 on both sides. But you can also leave it.
x - 2 = 0
x = 2
x - 7 = 0
x = 7
If x = 2 then y = 7
If x = 7 then y = 2
Answer:
or 
rounded to the nearest tenth
Step-by-step explanation:
1. Find the area of the base and the top, which are circles.
Area of circle : 
= 986.960440109
There are 2 circles, soooooo....= 986.960440109 x 2 = 1973.92088022
2. Find the rest of the area of the cylander.
So, we have to find the circumference of the circle.
Circumference :2
10 = 62.83
3. Multiply circumference by height.
62.83 x 7 = 439.81
4. Add all of the products.
439.81 + 1973.92088022 = or rounded to the nearest tenth
Y=Ix+1I-3
the absolute value of( x+1) minus 3
It is the graph where the two lines intersect, when they intersect there is a point where they connect, and that is your answer
