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2 years ago

Harold swam 6 2/5 km in 2 hours how far could Harold swim in 5 hours

Mathematics

1 answer:

Mama L [17]2 years ago

4 0

The distance that Harold swim in 5 hours should be 16 km.

Given that,

Harold swam 6 2 ÷ 5 km in 2 hours.
And, the number of hours given is 5 hours.

Here we assume the distance be x

So,

$6\frac{2}{5}$ =6.4

Now

$\frac{6.4}{2}=\frac{X}{5}$

2x=(6.4)(5)

2x=32

Now Divide by 2 on both sides

Thus,

X=16 km

Therefore, we can conclude that the distance that Harold swim in 5 hours should be 16 km.

Learn more about the distance here: brainly.com/question/12319416

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The function f(x) = –x2 + 20x – 75 models the profit from one customer, in dollars, a shop makes for printing photos, where x is

trasher [3.6K]

The function is graphed as shown below

Part A:

We use the formula $- \frac{b}{2a}$ to find the vertex of the function. A quadratic function of the form of $a x^{2} +bx+c$ and equating this form to the given function $- x^{2} +20x-75$ , we have
$b=20$ and $a=-1$ .

Substituting $a$ and $b$ into the vertex formula, we have
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This calculation means that the highest profit is achieved when the number of photo printed equals to ten photos

Part B:

We can find solution to this equation by factorising

$- x^{2} +20x-75=0$
$-( x^{2} -20x+75)=0$
$x^{2} -20x+75=0$
$(x-5)(x-15)=0$
$x=5$ and $x=15$ , as shown in the graph

The two values means that the company makes no profit when they either produce 5 or 15 photos

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Thea scored an average of 13 points per game in her first 5 basketball games. In her 6th game, the average changed to 17 points

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Answer: Her score for the 6th game as 37.
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Step-by-step explanation:

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